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vivado [14]
3 years ago
15

FIND THE RECIPROCAL OF 3 4/9

Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

9/31

Step-by-step explanation:

For a fraction, the reciprocal is just a different fraction, with the numbers "flipped" upside down (inverted). Any number times its reciprocal will give you 1.

3\frac{4}{9} * \frac{9}{31} = 1

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Which expression is equivalent to (x^1/2y^-1/4z)^-2?
tiny-mole [99]

Answer:

y^1/2/xz^2 option 3

Step-by-step explanation:

(x^1/2 y^-1/4 z)^-2= x^(-1/2*2) y^(1/4*2) z^-2= x^-1 y^1/2 z^-2= y^1/2/xz^2

7 0
3 years ago
Can anyone answer these?
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4 0
3 years ago
henry has 68 miles to destination after 45 minutes and 51.5 miles to destination after 71 minutes of driving. How many miles to
Airida [17]
Let d represent the distance of the destination from the starting point.

After 45 min, Henry has already driven d-68 miles.  After 71 min., he has already driven d-51.5 miles.

So we have 2 points on a straight line:

(45,d-68) and (71,d-51.5).  Let's find the slope of the line thru these 2 points:

                                 d-51.5 - (d-68)         16.5 miles
slope of line = m = ----------------------- = ------------------
                                     71 - 45                   26 min

Thus, the slope, m, is   m = 0.635 miles/min

The distance to his destination would be d - (0.635 miles/min)(79 min), or 

d - 50.135 miles.  We don't know how far his destination is from his starting point, so represent that by "d."

After 45 minutes:  Henry has d - 68 miles to go;

After 71 minutes, he has        d - 51.5 miles to go; and

After 79 minutes, he has         d -  x miles to go.  We need to find x.

Actually, much of this is unnecessary.  Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is

(0.635 miles/min)(8 min) = 5.08 miles.  Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.




7 0
3 years ago
I need some help on this ​
Musya8 [376]

Answer: A

Step-by-step explanation: A function means that your x can only have one y but your y can have multiple x's.

8 0
3 years ago
If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?
Andreas93 [3]

Until now, given a function  f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given  f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and  

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.  

 

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of  exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find  f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0
3 years ago
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