Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
(15√6 / √5)
<span>(15√6/√5) *(</span>√5/√5)
(15*√6*√5)/(√5*√5)
15*√30 / 5
3√30
Answer:
Step-by-step explanation:
T(1)=1=0*x^3 0*x^2 0*x 1*1 T(x)=x-1=0*x^3 0*x^2 1*x (-1)*1 T(x^2)=2x^2-6x 6=0*x^3 2*x^2 (-6)*x 6 T(x^3)=6x^3-48*x^2 141*x-141 T(x^4)=24*x^3-204*x^2 628*x-604*1 collect the coefficient matrix and take its transpose
0 0 0 6 24
0 0 2 -48 -204
0 1 -6 141 628
1 -1 6 -141 -604
Solve: 4(6x - 10) = 8x + 40
A 0
B.5/2
c. 23
D. 5
<h3><u>Answer:</u></h3>
Option D
The solution to given equation is x = 5
<h3><u>Solution:</u></h3>
Given that we have to solve the given equation
4(6x - 10) = 8x + 40
Let us solve the above expression and find value of "x"
Multiplying 4 with terms inside bracket in L.H.S we get,
24x - 40 = 8x + 40
Move the variables to one side and constant terms to other side
24x - 8x = 40 + 40
Combine the like terms,
16x = 80
Thus solution to given equation is x = 5
