How do graph an inequality

If sin(a) = cos(2a), then what is the value of a?

Mariulka [41]

Answer:

-90 , 30

Step-by-step explanation:

sina = cos(2a)

= 1 - 2(sina)^2

2(sina)^2 + sina -- 1 = 0

( sina + 1 )( 2sina - 1 ) = 0

sina = -1 or sina = 1/2

=> a = -90 degrees or => a = 30 degrees

3 0

3 years ago

Plz answer asap!!!!!!

Hoochie [10]

Answer:

y = 9

Step-by-step explanation:

m<1 + 2x = 180° because these angles are supplementary

61° + 2x° = 180°

2x = 180 - 61

2x = 119 divide both sides by 2

x = 59.5

Since f is parallel to s:

2x + (7y-2) = 180°

2×59.5 + 7y - 2 = 180

119 + 7y - 2 = 180

7y = 180 - 117

7y = 63 divide both sides by 7

y = 9

8 0

3 years ago

Will and tommie bought a giant candy bar composed of 24 pieces. Will ate 1/4 of the bar and Tommie ate 2/3 of the bar. How many

hichkok12 [17]

Answer:

3/24 or 1/8

Step-by-step explanation:

1. convert 1/4 and 2/3 into fractions with common denominators of 24 (since there are 24 pieces.

2. find the multiples of 4 and 3

4, 8, 12, 16, 20, 24 = 5

3, 6, 9, 12, 15, 18, 21, 24 = 8

3. convert the fractions

1/4 * 5/5 = 5/24

2/3*8/8 = 16/24

4. add the fractions.

5/24 + 16/24 = 21/24

5. subtract 21/24 from 24/24 = 3/24

6. reduce by dividing both terms by 3 = 1/8

6 0

3 years ago

Trapezoid ABCD is graphed in a cordinate plane

alukav5142 [94]

Answer:

the answer to you're question is 32 square units

5 0

3 years ago

in a study of red/green color blindness, 600 men and 2150 women are randomly selected and tested. Among the men, 56 have red/gre

Umnica [9.8K]

Answer:

z=13.36 (Statistic)

$p_v =P(Z>13.36)\approx 0$

The p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of men with red/green color blindness is significant higher than the proportion of female with red/green color blindness .

Step-by-step explanation:

1) Data given and notation

$X_{MCB}=56$ represent the number of men with red/green color blindness

$X_{WCB}=5$ represent the number of women with red/green color blindness

$n_{MCB}=600$ sample of male selected

$n_{WCB}=600$ sample of demale selected

$p_{MCB}=\frac{56}{600}=0.093$ represent the proportion of men with red/green color blindness

$p_{WCB}=\frac{5}{2150}=0.0023$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men with red/green color blindness is a higher than the rate for women , the system of hypothesis would be:

Null hypothesis: $p_{MCB} \leq p_{WCB}$

Alternative hypothesis: $p_{MCB} > \mu_{WCB}$

We need to apply a z test to compare proportions, and the statistic is given by:

$t=\frac{p_{MCB}-p_{WCB}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{MCB}}+\frac{1}{n_{WCB}})}}$ (1)

Where $\hat p=\frac{X_{MCB}+X_{WCB}}{n_{MCB}+n_{WCB}}=\frac{56+5}{600+2150}=0.0221$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.093-0.0023}{\sqrt{0.0221(1-0.0221)(\frac{1}{600}+\frac{1}{2150})}}=13.36$

4) Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =P(Z>13.36)\approx 0$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of men with red/green color blindness is significant higher than the proportion of female with red/green color blindness .

4 0

3 years ago