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3 years ago

Given points A(4,5) and B(-4,11). Find the distance AB to the nearest tenth.

Mathematics

2 answers:

Arisa [49]3 years ago

6 0

10 should be the answer

Viefleur [7K]3 years ago

3 0

If A(x', y') & B(x",y") the the distance AB is given by the following formula:

AB =√[(x"-x')² + (y"-y')²]

Plug into the above with A(4,5) and B(-4,11).

AB =√[(-4-4)²+(11-5)²] =√(-8)²+(6)² = √(64) + (36) =√100 = 10

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Write the values that make the denominators zero. then solve the equation?

Olin [163]

Answer:

denominators are zero for x=1

there is no solution

Step-by-step explanation:

We suspect your equation is supposed to be ...

10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators

The denominators will be zero for x=1.

This version of the equation has no solution. It simplifies to ...

2/(x-1) + 1/5 = 2/(x -1)

1/5 = 0 . . . . . subtract 2/(x-1) from both sides

There is no value of x that will make this equation true.

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Alternative interpretation

The way your equation is written, it must be interpreted according to the order of operations to be ...

(10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero

2x -3.8 = 2/x

2x^2 -3.8x = 2 . . . . multiply by x

2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)

(x -0.95)^2 = 1.9025

x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}

4 0

3 years ago

The coordinates of the vertices of the triangle are

Alecsey [184]

The area of the triangle PQR is 108 square units

<h3>How to determine the area of the triangle?</h3>

The given parameters are:

Height, h = 12 units
Base, b = 18 units

The area is then calculated using:

Area = 0.5 * base * height

So, we have:

Area = 0.5 * 18 * 12

Evaluate

Area = 108

Hence, the area of the triangle PQR is 108 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ2

6 0

2 years ago

Read 2 more answers

3) Emma is great at the standing long jump. Her best jump is 10 feet 8 inches. How many

givi [52]

Answer:

128 inches

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How do you convert a mixed fraction to an improper fraction ?

maks197457 [2]

Answer:

see the explanation

Step-by-step explanation:

we know that

A mixed number is equal to sum a integer plus a fraction less than 1. The result is a fraction where the numerator will be always greater than the denominator (This fraction is called an improper fraction)

Example

$a\frac{b}{c}$ ----> a mixed number

a is a integer

b/c < 1

$a\frac{b}{c}=a+\frac{b}{c}$

Adds the integer plus the fraction

$\frac{ac+b}{c}$ ---> an improper fraction

$\frac{ac+b}{c} > 1$

8 0

3 years ago

Calculate the length of sides triangle pqr and determine weather or not triangle is a right angled. P(-4,6) q(6,1) r(2,9)

Tom [10]

$\bold{\huge{\underline{ Solution }}}$

<h3>Given :-</h3>

We have given the coordinates of the triangle PQR that is P(-4,6) , Q(6,1) and R(2,9)

We have to calculate the length of the sides of given triangle and also we have to determine whether it is right angled triangle or not

<h3>Let's Begin :-</h3>

Here, we have 

Coordinates of P =( x1 = -4 , y1 = 6)
Coordinates of Q = ( x2 = 6 , y2 = 1 )
Coordinates of R = ( x3 = 2 , y3 = 9 )

By using distance formula 

$\pink{\bigstar}\boxed{\sf{Distance=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

Subsitute the required values in the above formula :-

Length of side PQ

$\sf{ = }{\sf\sqrt{ (6 - (-4))^{2} + (1 - 6)^{2}}}$

$\sf{ = }{\sf\sqrt{ (6 + 4 )^{2} + (- 5)^{2}}}$

$\sf{ = }{\sf\sqrt{ (10)^{2} + (- 5)^{2}}}$

$\sf{ = }{\sf\sqrt{ 100 + 25 }}$

$\sf{ = }{\sf\sqrt{ 125 }}$

$\sf{ = 5 }{\sf\sqrt{ 5 }}$

Length of QR

$\sf{ = }{\sf\sqrt{(2 - 6)^{2} + (9 - 1)^{2}}}$

$\sf{ = }{\sf\sqrt{(- 4 )^{2} + (8)^{2}}}$

$\sf{ = }{\sf\sqrt{16 + 64 }}$

$\sf{ = }{\sf\sqrt{80 }}$

$\sf{ = 4 }{\sf\sqrt{5 }}$

Length of RP

$\sf{ = }{\sf\sqrt{ (-4 - 2 )^{2} + (6 - 9)^{2}}}$

$\sf{ = }{\sf\sqrt{ (-6 )^{2} + (-3)^{2}}}$

$\sf{ = }{\sf\sqrt{ 36 + 9 }}$

$\sf{ = }{\sf\sqrt{ 45 }}$

$\sf{ = 3}{\sf\sqrt{ 5 }}$

We have to determine whether the triangle PQR is right angled triangle

<h3>Therefore, </h3>

By using Pythagoras theorem :-

Pythagoras theorem states that the sum of squares of two sides that is sum of squares of 2 smaller sides of triangle is equal to the square of hypotenuse that is square of longest side of triangle

That is,

$\bold{ PQ^{2} + QR^{2} = PR^{2}}$

Subsitute the required values,

$\bold{ 125 + 80 = 45 }$

$\bold{ 205 = 45 }$

From above we can conclude that,

The triangle PQR is not a right angled triangle because 205 ≠ 45 .

6 0

3 years ago