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vitfil [10]
4 years ago
7

Given points A(4,5) and B(-4,11). Find the distance AB to the nearest tenth.

Mathematics
2 answers:
Arisa [49]4 years ago
6 0
10 should be the answer
Viefleur [7K]4 years ago
3 0
If A(x', y') & B(x",y") the the distance AB is given by the following formula:

AB =√[(x"-x')² + (y"-y')²]

Plug into the above with A(4,5) and B(-4,11).

AB =√[(-4-4)²+(11-5)²] =√(-8)²+(6)² = √(64) + (36) =√100 = 10
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Answer:

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Step-by-step explanation:

Step 1:   Find the slope

slope m = (y2 - y1)(/x2 - x1)

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Step 1:  Use the formula y = mx + b to solve

This is slope-intercept form of a line.  We have a slope of 3/2, and a point (x, y), which is (1, 1).  Plug those values into the equation above and solve for b (the only variable we are missing

1 = (3/2)(1) + b

   1 = 3/2 + b  

          1 - 3/2 = b

             2/2 - 3/2 = b

                  -1/2 = b

Step 2: Rewrite the formula using the slope and the b value we just calculated

 y = (3/2)x - 1/2

Step 3:  Standard form of a line is ax + by = c, where a is a positive integer, so we rearrange the equation from step 2 to standard form.  

y = (3/2)x - 1/2

 -(3/2)x + y = -1/2     (subtract (3/2)x from both sides)

 

      -3x + 2y = -1       (multiply by 2 to get rid of the fraction on x)

           3x - 2y = 1     (multiply by -1 so a becomes positive)    

3 0
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Alecsey [184]

Answer:

you will earn 4000 after 5 yr.

Step-by-step explanation:

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5 0
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Answer:

Step-by-step explanation:

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3 years ago
Kite DCFE is inscribed in circle A shown below.
kogti [31]

Answer:

∠DEF =56°

Step-by-step explanation:

We are given that arc DEF = 248°

So, arc DCF = 360°-248°

arc DCF = 112°

Now we are required to find the ∠DEF.

So, we will use Inscribed angle theorem.  

Inscribed angle theorem: The measure of an inscribed angle is equal to one-half the measure of its intercepted arc.  

Intercepted arc = arc DCF = 112°

Inscribed angle = ∠DEF

⇒∠DEF = \frac{1}{2}arcDCF

⇒∠DEF = \frac{1}{2}\times 112^{\circ}

⇒∠DEF =56°

Hence the measure of ∠DEF =56°

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3 years ago
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