I require assistance once again.
2 answers:
Answer:
Step-by-step explanation:
1. Equation changed to slope-intercept as thus
y = 490 - 0.667x
with slope = -0.667
intercept on y axis = 490
intercept on x axis = 735
2. Description about graphing the line using slope-intercept method
On the y (vertical axis): maximum value of y = 490 and that is when x = 0
On the x (horizontalal axis): maximum value of x = 735 and that is when y = 0
Incrementing on x axis cause a decline of y-axis (as shown in the graph as attached)
3. Equation of the function notation
F(x) = 490 - 0.667x
where wrap, y= F(x) and sandwich, x
4. See attached graph but try and continue the projection to intercept x at 735
5. Equation for next month is 2x + 3y = 1593
For the graph;
Slope remains the same as previous month = -0.667
intercept on y axis = 531
intercept on x axis = 796.5
The graphs look a little similar just that the intercepts are different.
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Answer:
Step-by-step explanation:
I am assuming the tank starts empty. It means that in 1 hour the tank has half that water, or 3600 gallons. And the good thing of lines passing through 0.0 is that the value at 1 IS the slope we need. ie 3600.
At this point it's easy to find that if in 2 hours it filled 1/10th of the tank, in 20 hours the tank will be full.
Graph done with paint, obviously not to scale.
