(−m)(n)p(3m−5n+7p)
=((−m)(n)p)(3m+−5n+7p)
=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)
=−3m^2np+5mn^2p−7mnp^2
I do believe you are right
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
(a/b) x (c/d) = (a*c)/(b*d)
Therefore:
(9/4) x (1/3) = (9*1)/(4*3) = 9/12 = 3/4
Answer:
3/4
