Let’s set this equation up to make this easier.
melanie= 2 1/5 miles walked
cathy= 1 3/4 more times than melanie.
when an equation says the word, more than this means adding. when it says less than this means subtraction. when it says times (in this question) then multiply.
so, if cathy walked 1 3/4 more times than melanie what we would do is multiply 1 3/4 to what melanie was walking. so 2 1/5 times 1 3/4 which equals 3.85.
so overall, cathy walked 3.85 more miles than melanie.
Answer:
19
Step-by-step explanation:
Given 2 sides of a triangle then the third side x is
difference of 2 sides < x < sum of 2 sides , that is
18 - 2 < x < 18 + 2
16 < x < 20
Then the largest possible length of the third side is 19
The slope is the rate in which he is moving and the y-intercept is where he started (at 0 seconds and 0 meters).
<h3>
Answers:</h3>
angle FHG = 42 degrees
angle GHI = 100 degrees
=========================================================
Explanation:
FHI is the largest angle. It is split into two pieces FHG and GHI which have measures of (3x+6) and (9x-8) degrees respectively.
Put another way, those two smaller angles (FHG and GHI) combine to form the larger angle (FHI)
This is the angle addition postulate.
------------------
(angle FHG) + (angle GHI) = angle FHI
(3x+6) + (9x-8) = 142
3x+6+9x-8 = 142
(3x+9x) + (6-8) = 142
12x - 2 = 142
12x-2+2 = 142+2 ... adding 2 to both sides
12x = 144
12x/12 = 144/12 .... dividing both sides by 12
x = 12
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Use that x value to find the angles we're after
angle FHG = 3x+6 = 3*12+6 = 36+6 = 42
angle GHI = 9x-8 = 9*12-8 = 108-8 = 100
Note how
(angle FHG) + (angle GHI) = 42 + 100 = 142
which is the measure of angle FHI. This confirms the answers.
Answer:
Step-by-step explanation:

