Question

Please help! enter a range of values for x:

Answer 1

Answer:

Step-by-step explanation:

using sine formula

let ∠ADB=y

then ∠CDB=180-y

∠DAB =180-(35+y)

$\frac{AB}{sin~y} =\frac{12}{sin ~35}} \\AB=\frac{12 sin y}{sin 35} \\\frac{BC}{sin(180-y)} =\frac{4x-4}{sin 20 } \\\frac{BC}{sin y} =\frac{4x-4}{sin 20} \\BC=\frac{(4x-4)sin y}{sin 20} \\But~AB=BC (given)\\\frac{12 sin y}{sin 35} =\frac{(4x-4)sin y}{sin 20} \\\frac{4x-4}{sin 20} =\frac{12}{sin 35} \\4(x-1)=\frac{12 sin 20}{sin35} \\x-1=\frac{3 sin 20}{sin35} \approx 1.789\\x \approx 2.789$