Find the size of each of the interior angles in a regular pentagon
1 answer:
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Answer:
g(x) = (1/6)(x +7)^2 -8
Step-by-step explanation:
The transformation ...
g(x) = a·f(x -h) +k
represents vertical scaling by a factor of 'a', right shift by h units, and up shift by k units. You want the function g(x) for f(x) = x^2, a = 1/6, h = -7, and k = -8. Those transformations give you ...
g(x) = (1/6)(x +7)^2 -8
<span>As x approaches positive infinity, f(x) approaches negative infinity, since the graph goes down</span>
