Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
<h2>
Answer:</h2>
<h3>7</h3>
<h2>
Step-by-step explanation:</h2>
<h2>Hope it help you </h2>
Answer:
Step-by-step explanation:
The experimental probability is based on what already happened.
So we see that both of them found a total of 11 + 3 + 36 + 40 + 134 = 224 coins.
The coins that are worth MORE THAN 10 cents are 11 quarters and 3 fifty-cent pieces (we exclude dimes because we want MORE THAN 10 cents, NOT 10 cents exactly).
So 11 + 3 = 14 coins are worth MORE THAN 10.
So the probability of finding one worth more than 10 cents next is 14/224 = 1/16
Answer:
it is really just 12-10 because 10 is negative think of it as you are taking away ten from the original 12 you have so the answer is 2
Answer:
x = 
y + 20
[Given]
4x - 6y = 20
[Add 6y to both sides of the equation]
4x = 6y + 20
[Divide both sides of the equation by 4]
x = 
y + 20
[Simplify , both 6 and 4 are divisible by 2]
x = y + 20
