You would is this case use the perfect square rule. So your would squareroot 9r^2 and 25 to get 3r+5 then you would square this equation to get (3r+5)^2
Answer:
Step-by-step explanation:
the value of the 4 in 6.14 is 0.04.
this is because the 4, or in this case 0.04
is in the hundredths place. So it is
suppose to have 0, where the 6 goes (also
the ones or units) The decimal point, another 0
where the 1 goes, ( the tenths) and finally back
to the 4. (Like I said, it’s the hundredths place)
so there you have it. Your answer will be 0.04
So, we need to find { curved surface area[pi*d*h] + top area[pi*(d^2)/4] }
just
substitute.
Answer:
New mean=71.32
Step-by-step explanation:
The expression for the total initial score is;
T=M×S
where;
T=total initial score
M=mean score
S=number in the set
replacing;
T=unknown
M=72
S=17
replacing;
T=72×17=1,224
The total initial score=1,224
Determine the total score by;
total score=total initial score+total final score
where;
total initial score=1,224
total final score=(68+63)=131
replacing;
total score=1,224+131=1,355
Determine the new mean;
New mean=total score/new number
where;
total score=1,355
new number=(17+2)=19
replacing;
new mean=1,355/19=71.32
Answer:
Step-by-step explanation:
From the graph attached,
Coordinates of the vertices are,
Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)
Following the rule of translation by 3 units to the right and 2 units down 
(x, y) → (x+3, y-2)
Q(1, 3) → Q''(4, 1)
R(3, -3) → R"(6, -5)
S(0, -2) → S"(3, -4)
T(-2, 1) → T"(1, -1)
Following rule
(rotation of a point by 180° about the origin) will give the image points,
(x, y) → (-x, -y)
Q"(4, 1) → Q'(-4, -1)
R"(6, -5) → R'(-6, 5)
S"(3, -4) → S'(-3, 4)
T"(1, -1) → T'(-1, 1)