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Rainbow [258]
3 years ago
15

Area of the shaded segment=

Mathematics
2 answers:
Serggg [28]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The area of the shaded segment

= area of sector OAB - area of ΔOAB

area of sector = area of circle × fraction of circle, that is

A = πr² × fraction of circle

  = π × 6² × \frac{60}{360}

  = 36π × \frac{1}{6} = 6π units²

Area of triangle = 0.5 × 6 × 6 × sin60° = 18 × \frac{\sqrt{3} }{2} = 9\sqrt{3} units²

Hence

area of shaded segment = 6π - 9\sqrt{3} units² → A

Temka [501]3 years ago
5 0

Answer:

<u><em>Answer in Picture Below</em></u>

Step-by-step explanation:

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A line passes through the point (8,-8) and has a slope of 3/4. Write an equation in slope-intercept form for this line.
Soloha48 [4]

Answer:

Step-by-step explanation:

y + 8 = 3/4(x - 8)

y + 8 = 3/4x - 6

y = 3/4x - 14

8 0
3 years ago
Mr Martin has 120 CDs. The ratio of indie CDs to dance CDs is 5:7. How many of each type of CDs does he have.
algol [13]

Answer

Martin has 50 indie CDs and 70 dance CDs

Step-by-step explanation:

5+7=12 120/12 =10 10x5=50 and 10x7=70 So Martin has 50 indie cds and 70 dance CDs

4 0
3 years ago
What is the difference of setting up a subtraction and addition decimal problem from setting up a multiplication decimal problem
Leya [2.2K]
Answer: During subtraction or addition, the original numbers don’t change; meaning, you pay attention to decimal points and line up the existing points to the correct decimal slot.

Ex. 5.34
+126.01
131.35

However during multiplication, setting up the problem would be disregarding the decimal points from the start.

Ex. if you have 5.34 x 126.01, you would solve it as 534 x 12601 to begin, then count the number of digits after each factor. so 2 from 5, and 2 from 6, accumulating 4. Take the number you get from the first multiplication process and move it 4 digits to the left; now you have your final answer.
6 0
3 years ago
WILL GIVE BRAINLIEST!
Blizzard [7]

Answer:

1 1/3

Step-by-step explanation:

it's bc the number is closer to one and not in the middle. have a great day

7 0
2 years ago
Read 2 more answers
In how many ways can a quality-control engineer select a sample of3 transistors for testing frm a batch of 100 transistors?
Advocard [28]

Answer:

161700 ways.

Step-by-step explanation:

The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

3 transistors from a set of 100. So

C_{100,3} = \frac{100!}{3!(100-3)!} = 161700

So 161700 ways.

6 0
3 years ago
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