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bezimeni [28]
3 years ago
6

Help me please!!!!!!

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

the answer is (6,1)

Step-by-step explanation:

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According to my teacher she says its b
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The square root of 9x^3/5y^2 show your work. (Do not forget to rationalize the denominator)
Maslowich

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I believe it would be 9.

9–√2

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All roots:

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9 is a perfect square

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Evaluating integral by net area
N76 [4]

The graph of f(x)=2 is a horizontal line. So the area under f(x) on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of g(x)=\sqrt{64-x^2} is the upper half of a circle with radius \sqrt{64}=8. It's symmetric about x=0, so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is \frac{\pi 8^2}4=16\pi.

Then use the fact that the definite integral is distributive over sums, meaning

\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi

8 0
4 years ago
When x-y=3 work out the value of y-x
GalinKa [24]

The value of y-x is (-3)

<u>Solution:</u>

Given: The value of x-y=3

To find: The value of y-x

\bold{x-y=3\rightarrow (1)}

Let's multiply the equation (1) by (- 1) on both sides,

\Rightarrow\bold{(x - y)\times(- 1) = 3\times(- 1)}

\Rightarrow\bold{-(x-y)=-3}

On multiplying the sign,

\Rightarrow\bold{(-x+y)=-3}

The above equation can also be written as,

\Rightarrow\bold{y-x=-3\rightarrow \text{(The required equation)}}

<u>Multiplication of signs:</u>

\Rightarrow( + )\times( + ) = ( + )

\Rightarrow( + )\times( - ) = ( - )

\Rightarrow( - )\times( + ) = ( - )

\Rightarrow( - )\times( - ) = ( + )

In simpler terms, when we multiply two integers with the same signs, the result is always positive and when we multiply two integers with different signs, the result is always negative.

5 0
3 years ago
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