Step-by-step explanation:
it's an Equilateral triangle
the base angels are equal
A=100°
B=40°
C=40°
Answer:
4 toppings
Step-by-step explanation:
22-12=10
2.50*?=10
2.50*4=10
4 toppings
Answer:
Point Critical point
Q (2,0) local minimum
R (-2,1) Saddle
S (2,-1) local maximum
T ( -2,-1) Saddle
O ( -2,0) Saddle
Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE
f(x,y) = x³ +y⁴ - 6x -2y² +3
df/dx = f´(x) = 3x² -6x
df/dxdx = f´´(xx) = 6x
df/dy = f´(y) = -4y
df/dydy = 4
df/dydx = df/dxdy = 0
df/dydy = f´´(yy)
D = [ df/dxdx *df/dydy] - [df/dydx]²
D = (6x)*4 - 0
D = 6*2*4 D > 0 and the second derivative on x is 6*2 = 12
so D > 0 and df/dxdx >0 there is a local minimum in P
Q(2,1)
D = (6*2)*4 D>0 and second derivative on x is 6*2
The same condition there is a minimum in Q
R ( -2,1)
D = 6*(-2)*4 = -48 D< 0 there is a saddle point in R
S (2,-1)
D = 6*2*4 = 48 D > 0 and df/dxdx = 6*-1 = -6
There is a maximum in S
T ( -2,-1)
D = 6*(-2)*(4) = -48 D<0 there is a saddle point in T
O ( -2,0)
D = 6*(-2)*4 = -48 D<0 there is a saddle point in O
Answer:
C) 119.75 + 2.25p <= 500; p <= 169
Step-by-step explanation:
My friend, for this problem you must realize that there is a fixed cost of 119.75 that we add always. Then $2.25 per pastry manufactured is also part of the total costs. Thus, we add both of them where p represents pastry to get 119.75 + 2.25p.
But, the question says the shopkeeper would like to stay under or be exactly at $500 for total costs. Thus, for this inequality, we set this equation as being <u>less than equal to 500.</u>
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Solve for p by adding 119.75 on both side and dividing both sides by 2.25 afterwards and you get 169.
