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4 years ago

10

suppose your school sells a total of 1139 tickets for a basketball game. An adult ticket cost $5. A student ticket cost $1. The

sponsors collect $3067 in ticket sales. Find the number of each type of ticket sold.

1 answer:

Wewaii [24]4 years ago

3 0

Answer:

look at picture

Step-by-step explanation:

x: adult tickets

y: student tickets

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Consider the graph with four lines below. On a coordinate plane, line a has a positive slope and goes through points (negative 1

yan [13]

Answer:

The correct option is;

line a and line b

Step-by-step explanation:

Lina a passes through (-1, 0) and (1, 2)

Line b passes through (2, 2) and (-1, -1)

Line c passes through (0, 3) and (1, 0)

Line d passes through y = 1

An equation that has no solution

By examination, from the plot of the coordinates using an online tool, the system that would have no solution is the system of line a and line b because they are parallel lines and cannot meet or have a point where there is a common solution, therefore, there are no solutions when the equations of the two lines are combined in one equation

Slope of line a = -2/-2 = 1

Slope of line b = 3/3 = 1

The slopes of lines a and b are equal, therefore, line a and line b are parallel.

5 0

4 years ago

Convert the following unsigned binary number to unsigned decimal.<br><br> 110011.101

tangare [24]

Answer:

51.625

Step-by-step explanation:

Given a unsigned binary number, to calculate the unsigned decimal:

first, starting at dot, you list the positive powers of 2 from right to left beginning in $2^{0}$ that is equal to “1”. Increase by one the exponent in every power until you complete the total quantity of digits from the unsigned binary number. In this case, since dot to the left, the binary number has six digits (110011). That is to say that you get the followings powers: $2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ .

Second, do the same from dot to the right but this time, you list the negative powers of 2 from left to right beginning in $2^{-1}$ that is equal $\frac{1}{2}$ = 0.5. so you get: $2^{-1}$ $2^{-2}$ $2^{-3}$

Now, join two parts and you get:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

Then, you write the equivalent of each of the power below from corresponding binary digit, like that:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

| | | | | | | | |

32 16 8 4 2 1 0.5 0.25 0.125

Finally, you write under the line the equivalent of each power that corresponding to “1” and write “0” under the line, the one that corresponding to “0”, and you sum each one of finals values. Like that:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

| | | | | | | | |

32 16 8 4 2 1 0.5 0.25 0.125

_______________________________________

32 16 0 0 2 1 0.5 0 0.125

32 + 16 + 0 + 0 + 2 + 1 + 0.5+ 0 + 0.125 = 51.625

So that the equivalent from unsigned binary number 110011.101 to unsigned decimal is 51.625

5 0

3 years ago

Pls help me 20 points

horsena [70]

Answer: 36

Step-by-step explanation:

-3 to the power of -2 is 9

2 to the power of 1 is 4

when you multiply that u get 36

3 0

3 years ago

A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.

Paladinen [302]

Answer:

Answer:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

.

Where xx is the number of small boxes sent and yy is the number of large boxes sent.

Step-by-step explanation:

Let be xx the number of small boxes sent and yy the number of large boxes sent.

Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:

20x+30y=28020x+30y=280

According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:

y=4xy=4x

Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

.

7 0

3 years ago

Given ƒ(x) = 9x + 54, find x when ƒ(x) = 18. <br> A)−6 B)−4 C)3 D)8

Katen [24]

Answer:

B. -4

Step-by-step explanation:

We want to find x such that f(x)=18.

We need to therefore solve 9x+54=18 forx.

9x+54=18

Divide both sides by 9:

(9x+54)/9=18/9

9x/9+54/9=18/9

Simplify:

x+6=2

Subtract 6 on both sides:

x=2-6

Simplify

x=-4.

So f(-4) should have value 18.

Let's check.

f(x)=9x+54

f(-4)=9(-4)+54

f(-4)=-36+54

f(-4)=18

So the answer is B.

7 0

4 years ago

Read 2 more answers