If I'm reading this correctly, it is 2*3*n*n = 6n^2
6n^2 = 54 Divide by 6
n^2 = 54/6
n^2 = 9 Take the square root of both sides.
sqrt(n^2) = sqrt(9)
n = +/- 3
n = + 3 or n = -3. Both will solve the equation above.
Edit
2 * 3 * n * n
Let n = 3
2 * 3 * 3 * 3 = 6 * 9 = 54
The other value is n = - 2
2 * 3 * n * n
2 * 3 * (-3) * (-3) A minus times a minus is a plus.
2 * 3 * 9 = 6 * 9 = 54
both + 3 and - 3 for n will give 54.
Answer:
-14
Step-by-step explanation:
First of all, we know that 5x^2+ ax+7x +5=0 only has one root. That means that b^2 - 4ac=0, and we can use this to find the discriminant, ax + 7x.
Now, if we simplified 5x^2+ ax+7x +5=0, by dividing it all by 5, it would be x^2+(a+7)/5x + 1 = 0.
After, we can plug what we know into the formula, b^2 - 4ac=0. It would be:
(a+7)^2 / 25 - 4 = 0
(a+7)^2 / 25 = 4
(a+7)^2 = 100
Since this is a square root, a+7 can be both negative or positive.
a+7= 10, or a+7 = -10
a=3, or a=-17
The question asks for the sum of a, which is 3 + (-17) = -14
Therefore, the answer is -14.
:) have fun with your rsm problems, assuming you got this from the portal.
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