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Juliette [100K]
3 years ago
9

Alpha Technologies, a newly established company, wants to share information about its work with people all over the world. Which

type of server should this company use to upload their information?
A. Web server

B. Mail server

C. Database server

D. File server
Computers and Technology
1 answer:
allochka39001 [22]3 years ago
6 0
It should use the web server to be accessible to users of World Wide Web across the world
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If you are installing separate anti-virus and anti-spyware programs, which should you install first
Vera_Pavlovna [14]
Probably the anti virus, so you don't get a virus from downloading the anti spyware program.
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3 years ago
Write code to take a String input from the user, then print the first and last letters of the string on one line. Sample run: En
Ainat [17]
<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

   //Begin the main method

    public static void main(String []args){

       

       

       //****create an object of the Scanner class.

       //Call the object 'input' to receive user's input

       //from the console.

       Scanner input = new Scanner(System.in);

       

       //****create a prompt to tell the user what to do.

       System.out.println("Enter the string");

       

       //****receive the user's input

       //And store it in a String variable called 'str'

       String str =  input.next();

       

       //****get and print the first character.

       //substring(0, 1) - means get all the characters starting

       //from the lower bound (index 0) up to, but not including the upper

       //bound(index 1).

       //That technically means the first character.

       System.out.print(str.substring(0,1));

       

       //****get and print the last character

       //1. str.length() will return the number of character in the string 'str'.

       //This is also the length of the string

       //2. substring(str.length() - 1) - means get all the characters starting

       // from index that is one less than the length of the string to the last

       // index (since an upper bound is not specified).

       // This technically means the last character.

       System.out.print(str.substring(str.length()-1));

       

       

       

    }  // end of main method

   

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
4c53f66d970acf88b251b2cf41bcdaf6.png
3 0
2 years ago
What is online school like 3 sentences
lara [203]

Answer:

its okay. i mean like you have to do a bunch off stuff. andsomtimes it gets a little boring.

Explanation:

i am doing online school.

3 0
3 years ago
Read 2 more answers
When would it be necessary to edit the information shown on an electronic business card?
Goryan [66]

Answer:

Really depends on your situation. If you specified, I'd have an asnwer

3 0
3 years ago
Read 2 more answers
5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
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