Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 30000
r = 6% = 6/100 = 0.06
n = 4 because it was compounded 4 times in a year.
t = 10 years
Therefore,.
A = 30000(1 + 0.06/4)^4 × 10
A = 30000(1 + 0.015)^40
A = 30000(1.015)^40
A = $54421
The amount of interest earned after 10 years is
54421 - 30000 = $24421
For number 12 you need to make an expression using the information given. a) 25g + 18r + 15b could be the expression.
b) The variables would be 25g for the 25 gold seats, 18r for the 18 red seats and 15b for the 15 blue seats.
c) Plug in the number given according to the variables.
25(100) + 18(250) + 15(200)
2500 + 4500 + 3000
7000 + 3000
$10,000
Answer:
- x +y = 500
- 0.65x +0.95y = 0.75(500)
- solution: (x, y) = (300, 200)
Step-by-step explanation:
A system of equations for the problem can be written using the two given relationships between quantities of brass alloys.
<h3>Setup</h3>
Let x and y represent the quantities in grams of the 65% and 90% alloys used, respectively. There are two relations given in the problem statement.
x + y = 500 . . . . . . quantity of new alloy needed
0.65x +0.90y = 0.75(500) . . . . . quantity of copper in the new alloy
These are the desired system of equations.
<h3>Solution</h3>
This problem does not ask for the solution, but it is easily found using substitution for x.
x = 500 -y
0.65(500 -y) +0.90y = 0.75(500)
(0.90 -0.65)y = 500(0.75 -0.65) . . . . . . subtract 0.65(500)
y = 500(0.10/0.25) = 200
x = 500 -200 = 300
300 grams of 65% copper and 200 grams of 90% copper are needed.
Answer:
32
Step-by-step explanation:
1 mile = 1.609 kilometers
if i remember correctly the answers should be :
(the < > don't have line on the bottom so ill type line if it needs it )
9. n < -8 (line)
10. r > 9/7
11. w < -7/4 (line)
12.y < -0.8