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Andrei [34K]
2 years ago
15

Henry goes to the carnival with 3

Mathematics
2 answers:
bixtya [17]2 years ago
8 0

Answer:

$5.50 x 5 =  $27.5

$27.5 x 4 =  110$

$2.00 x 2 = $4.00

$4.00

$3.00

$1.75 x 4 =  7$

27.5 + 110 + 4.00 + 4.00 + 3.00 + 7 = 155.5

Step-by-step explanation:

can you me as brainliest if its right?\

my first answer was wrong

Vladimir79 [104]2 years ago
7 0
3 x 5 = 15 rides
15 x 5.50 = $82.50
2 x 2 = $4
+ $2
+ 3
4 x 1.75 = $7
= $98.50
that’s what i got
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The function (x) = x is shown on the graph,
Sindrei [870]

Answer:

the domain of the function is all real numbers less than or equal to 0

3 0
2 years ago
Divide and write in simplest form 2 3/8 divided by 1 3/4
s344n2d4d5 [400]

First, change each mixed fraction into improper

2 3/8 = 19/8

1 3/4 = 7/4

The problem will look like: (19/8)/(7/4)

To solve, flip the second fraction, and change the division sign into a multiplication sign.

(19/8)/(7/4) = (19/8) x (4/7)

Multiply across

(19/8) x (4/7) = 76/56

Simplify.

76/56 simplified = 19/14

Change to mixed fraction

19/14 = 14/14 + 5/14 = 1 5/14

1 5/14 is your answer

hope this helps

7 0
4 years ago
HELP ME OUT PLEASE <br><br>Use the data to create a scatter plot. ​
disa [49]

Answer: i dont know if this will be correct but, the 2 goes on the bottom count 5 up so you will get the first one done, bottom 3 and count up 8, bottom 4 and count up to 13, its the same for all of them.

Step-by-step explanation:

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3 years ago
What is the absolute value of 3 above par
lubasha [3.4K]
The absolute value of 3 above par means any value more than the absolute value of 3. The absolute value of 3 is (+) 3 since an absolute value of a number cannot be negative. Above par means positive (+), so more than the specified value of 3. <span />
6 0
3 years ago
Read 2 more answers
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
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