For question 1 it would be 10 hundreds and 2 tens for the second question it would be 13 hundreds
1. -5x^10, because 4-9 is 5 and you don't do anything do the exponents when subtracting.
2. 9x^2-12x-6, quadratic trinomial
3. 5.5x^2+5.5x^2-9.2x+9.9x+9.6+1.3=
11x^2+0.7x+8.2
1 - a comparable
2 - ? what are the words to pick from
3- contradiction
Answer:
1. m = 6/5 or 1 1/5
2. m = -4/5
Step-by-step explanation:
1.) Find the slope of the line that contains (5,4) and (0,−2).
Slope m = (y2-y1)/(x2-x1)
m = (-2 - 4)/(0 - 5) = -6/-5 = 6/5
m = 1 1/5
2.) Find the slope of the line that contains (6,−2) and (−4,6).
Slope m = (y2-y1)/(x2-x1)
m = (6 - -2)/(-4 - 6) = 8/-10 = -8/10 = -4/5
Given:
Consider the height of the rocket, in feet after x seconds of launch is
To find:
The time at which the rocket will reach its max, to the nearest 100th of a second.
Solution:
We have,
It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.
If a quadratic function is , then the vertex is
Here, .
So,
So, x-coordinate of the vertex is 4.75.
Therefore, the rocket will reach its max at 4.75 second.