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3 years ago

Please help on 7 thank you so much

Mathematics

1 answer:

amm18123 years ago

7 0

Answer:

400 miles per inch

Step-by-step explanation:

divided 2800 by 7 and you get 400 so yeah

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What is the whole of 15% of is 12.

Morgarella [4.7K]

The whole would be 72

4 0

4 years ago

Write each polynomial in standard form and show your work. 2+3x+x^2 Plz help!

Artyom0805 [142]

The "standard form" of a 2nd order poly is y = ax^2 + bx + c. Therefore, your 2 + 3x + x^2 in "standard form" is y = x^2 + 3x + 2.

7 0

3 years ago

Create a linear regression equation that can be used to model the amount of money in the account (the balance), y, based on the

Karolina [17]

The regression equation is $\^y = 1.56\^x + 1.29$ , and it will take 31 weeks to have $50.00

(a) The linear regression equation

To do this, we make use of a graphing calculator;

From the graphing calculator, we have the following calculation summary:

The sum of X = 45
The sum of Y = 83
Mean X = 4.5
Mean Y = 8.3
Sum of squares (SSX) = 82.5
Sum of products (SP) = 128.5

The regression equation is then represented as:

$\^y = b\^x + a$

Where:

$b = \frac{SP}{SSX}$ and $a = M_Y - bM_X$

So, we have:

$b = \frac{128.5}{82.5}$

$b = 1.55758$

Approximate

$b = 1.56$

$a= 8.3 - (1.56 \times 4.5)$

$a= 1.29091$

Approximate

$a= 1.29$

This means that, the regression equation is $\^y = 1.56\^x + 1.29$

(b) Predict the time to have $50.00

This means that:

$\^y = 50$

So, we have:

$50 = 1.56\^x + 1.29$

Subtract 1.29 from both sides

$48.71 = 1.56\^x$

Divide both sides by 1.56

$31.22 = \^x$

Rewrite as:

$\^x = 31.22$

Approximate

$\^x = 31$

Hence, it will take 31 weeks to have $50.00

Read more about linear regression models at:

brainly.com/question/14585820

8 0

2 years ago

Each variable indicates different weights. Which weight can you find? Find it.

SOVA2 [1]

Answer:

We can only be certain that a weighs 12.

There are infinitely many possiblities for b and c.

Step-by-step explanation:

We have the equation:

$a+b+c+a+c+b+a+c=12+a+a+b+b+c+c+c$

Each variable indicates a weight.

We would like to determine the weights of each variable (if possible).

First, we can rearrange the equation to acquire:

$(a+a+a)+(b+b)+(c+c+c)=12+(a+a)+(b+b)+(c+c+c)$

We can combine like terms:

$3a+2b+3c=12+2a+2b+3c$

Notice that both sides have 2b and 3c. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2b and 3c from both sides. This yields:

$3a=12+2a$

Therefore, we can solve for a. Subtract 2a from both sides:

$a=12$

Hence, the weight of a is 12.

Using the newly acquired information, we can go back to our simplified equation:

$3a+2b+3c=12+2a+2b+3c$

Since a is 12:

$3(12)+2b+3c=12+2(12)+2b+3c$

Evaluate:

$36+2b+3c=12+24+2b+3c$

Simplify:

$36+2b+3c=36+2b+3c$

We can subtract 36 from both sides:

$2b+3c=2b+3c$

As you can see, this is a true statement.

Since this is a true statement, there are infinitely many possible values for b and c.

Therefore, the only weight we are certain of knowing is weight a weighing 12.

8 0

3 years ago

I need help please ?

valentinak56 [21]

the answer would be D.

4 0

3 years ago