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liraira [26]
3 years ago
9

What is the x-intercept in the equation y = 2x - 10?

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
4 0
X , y = 0

0 = 2x - 10
2x = 10
x = 5
AlekseyPX3 years ago
4 0
5 is the intercept i think

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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?
gladu [14]
Sum:

     3x^5*y - 2x^3*y^4 - 7x*y^3
 + -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
     -5x^5y - 6xy^3

Term 1: Degree = 6
Term 2: Degree = 4

Difference:

     3x^5*y - 2x^3*y^4 - 7x*y^3
 -  -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
     11x^5y - 4<span>x^3*y^4 - 8</span>xy^3

Term 1: Degree = 6
Term 2: Degree = 7
Term 3: Degree = 4

The degree of a term of a polynomial can be obtained by adding the exponents of the variables in that term.
5 0
4 years ago
10. In right triangle FGH shown below,
Vikki [24]

Applying the leg rule, and solving algebraically, the lengths are determined as:

JG = 9

HJ = 12

<h3>What is the Leg Rule?</h3>

The Leg rule states that when an altitude bisects the right angle of a right triangle and intersects the hypotenuse, then, hypotenuse/leg = leg/part.

Find length of JG using algebraic solutions and the leg rule:

Let JG = x

Hypotenuse = x + 16

Leg = 15

Part = x

Therefore:

(x + 16)/15 = 15/x (leg rule)

Cross multiply

x(x + 16) = (15)(15)

x² + 16x = 225

x² + 16x - 225 = 0

Factorize

(x + 25)(x − 9) = 0

x = -25 or x = 9

The length of JG (x) cannot be negative, therefore, the length of JG = 9.

Find length of JG using algebraic solutions:

Let HJ = y

Based on the altitude theorem, we would have:

y = √(16 × JG)

Substitute

y = √(16 × 9)

y = √(144)
y = 12

Therefore, the length of HJ is: 12.

Learn more about the leg rule on:

brainly.com/question/25016594

5 0
2 years ago
4) Solve for w: P = 4L + 4W
xxMikexx [17]

Answer:

Rewrite the equation as 4L+4W=P.

4L+4W=P

Subtract 4L from both sides of the equation.

4W=P−4L Divide each term by 4 and simplify.

W=P/4−L

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(02.04 MC)
Ainat [17]

(\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{18}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{18}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{3}}} \implies \cfrac{ 12 }{ 2 } \implies 6

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{ 6}(x-\stackrel{x_1}{3}) \\\\\\ y-6=6x-18\implies {\Large \begin{array}{llll} y=6x-12 \end{array}}

6 0
1 year ago
How do we solve this?
Harlamova29_29 [7]

Answer:

B is (3, 10)

Step-by-step explanation:

The midpoint of coordinates of the 2 points (x1, y1( and (x2, y2) is

(x1 + x^2) / 2 , (y1 + y2)/2.

So if (x, y) are the coordinates of B we have:

(7 + x)/2 + (2 + y)/2 = 5 + 6

So 7 + x = 2*5 so x = 3

AND 2 + Y = 12 SO y = 10.

4 0
3 years ago
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