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Ksivusya [100]
3 years ago
12

If f(x) = 2x - 4 and g(x)= -5x + 6, then what is f(g(x))?

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

B. f(g(x)) = -10x + 8

Step-by-step explanation:

When evaluating f(g(x)), substitute what g(x) is in place of g(x).

So instead of

f(g(x))

the function would be:

f(-5x + 6).

Now all you have to do is evaluate this.

To evaluate this function, substitute the value inside the f(x) for all instances of x in the equation.

f(x) = 2x - 4

f(-5x + 6) = 2(-5x + 6) - 4

f(-5x + 6) = -10x + 12 - 4

f(-5x + 6) = -10x + 8

Therefore, f(g(x)) = -10x + 8.

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We need to show whether

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we can also write it as:

y = e^x - 1

now all we have to do is to make x the subject of the equation.

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4 0
4 years ago
Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b
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Answer:

(a)

\bar x = 0.0075

s = 0.0049

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

n = 8

\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 &{|1 - 2|} &0.003 & 0.015 & 0.006 & 0.004 & 0.002 & 0.010 & 0.005 & 0.015 \ \end{array}

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

\bar x = \frac{\sum x}{n}

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\bar x = \frac{0.06}{8}

\bar x = 0.0075

Next, calculate the standard deviation (s).

This is calculated using:

s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}

So, we have

s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}s = \sqrt\frac{0.00019}{8}

s = \sqrt{0.00002375

s = 0.0049

Solving (b):

Of the given options (A - E), option B is correct because the sample is actually too small

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