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3 years ago

Find a unit vector that is orthogonal to both

Mathematics

1 answer:

Dafna11 [192]3 years ago

3 0

Answer: Find the answer in the explanation.

Step-by-step explanation: Please find the attached file for the solution

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Complete the following statement. Round to the nearest hundredth .

RSB [31]

f(x) = 3/(x + 2) - √x - 3

f(7) = 3/(7 + 2) - √7 - 3

f(7) = 3/9 - √4

f(7) = 0.333 - 2

f(7) = -1.67

7 0

3 years ago

What is the sum of 4.061 and 18.62?

andrezito [222]

Answer:

22.681

Step-by-step explanation:

4.061

+ 18.620

22.681

Hope this helps!! Have a wonderful day C:

6 0

3 years ago

Is 16x2 - 16x + 4 a perfect square?

Andrew [12]

Answer:

Yes

Step-by-step explanation:

Use the completing the square method:

16(x^2-x)+4

=16((x-1/2)^2 - (1/2)^2)+4

=16((x-1/2)^2 - 1/4)+4

=16((x-1/2)^2) - 16/4 + 4

=16(x-1/2)^2

=4^2(x-1/2)^2

The product of two square is itself a square.

5 0

3 years ago

Devaughn's age is three times Sydney's age. The sum of their ages is 84 . What is Sydney's age?

defon

the answer is 21 years old

4 0

3 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

7 0

3 years ago

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