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3 years ago

Which point can be use to create a right triangle that has AB as its hypotenuse? (Explain please!)

Mathematics

2 answers:

ioda3 years ago

6 0

If AB is the hypotenuse, we have to draw the legs of the triangle and see where they intersect. There are two different possibilities (see the picture attached below). Therefore, the answers are (-3,3) and (-8,-4).

ElenaW [278]3 years ago

5 0

Answer:

(-3,3)

Step-by-step explanation:

i hope this helped

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At a telethon, a volunteer can take 48 calls over a 4-hour shift. At this rate, how many calls can 12 volunteers take in a 4-hou

stellarik [79]

1 volunteer - 4 h - 48 calls
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The time is the same, so it's irrelevant.
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4 years ago

Need Help !!

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$\huge \mathbb{\green{\fbox{\pink{ANSWER}}}}$

$\\ \: \: \implies \: sin^{4} \: \theta + cos^{4} \: \theta \rightarrow \blue{ \frac{1}{2} }$

$\\ \\ \: \large \mathfrak \green{Solution} :$

$\\ \bf \: Given :$

$\\ \sf \: \: \bf sin \: \theta - cos \: \theta = 0$

$\\ \sf \rightarrow \: sin \: \theta = cos \: \theta$

$\\ \sf \rightarrow \: \frac{sin \: \theta} {cos \: \theta} = 1$

$\\ \sf \rightarrow \: tan \: \theta = 1$

$\\ \sf \rightarrow \: tan \: \theta = tan \: 45 \degree$

$\\ \sf \rightarrow \: \theta = 45 \degree$

$\\ \\ \therefore \: sin^{4} \: \theta + cos^{4} \: \theta$

$\\ \sf \rightarrow \: sin^{4} \: 45 \degree + cos^{4} \: 45 \degree$

$\\ \\\sf \rightarrow \: (\frac{1}{ \sqrt{2} } ) ^{4} +(\frac{1}{ \sqrt{2} } ) ^{4}$

$\\ \sf \rightarrow \: ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}} + ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}}$

$\\ \\\sf \rightarrow \: \frac{1}{2} × \frac{1}{2} + \frac{1}{2}× \frac{1}{2}$

$\\ \\ \sf \rightarrow \: \frac{1}{4} + \frac{1}{4}$

$\\ \\ \sf \rightarrow \: {\cancel \frac{2} {4}}$

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \fbox{\pink {\frac{1}{2}}}$

3 0

3 years ago

Read 2 more answers

PLEASE I NEED HELP URGENT I Will MARKE YOU BRAIN LIST

navik [9.2K]

Answer:

$1) \frac{1}{(x - 3)(x + 2)} + \frac{3}{(x + 2)(4 - x)} + \frac{2}{(x - 3)(x - 4)} \\ \\ = \frac{x - 4}{(x - 3)(x + 2)(x - 4)} - \frac{3(x - 3)}{(x - 4)(x + 2)(x - 3)} + \frac{2(x + 2)}{(x + 2)(x - 3)(x - 4)} \\ \\ = \frac{x - 4 - 3x + 9 + 2x + 4}{(x - 3)(x - 4)(x + 2)} \\ \\ = \frac{9}{(x + 2)(x - 3)(x - 4)}$

$2) \frac{2}{(x - 2)(x - 3)} + \frac{2}{(x - 1)(3 - x)} + \frac{1}{(1 - x)(2 - x)} \\ \\ = \frac{2(x - 1)}{(x - 1)(x - 2)(x - 3)} - \frac{2(x - 2)}{(x - 1)(x - 2)(x - 3)} + \frac{x - 3}{(x - 1)(x - 2)(x - 3)} \\ \\ = \frac{2x - 2 - 2x + 4 + x - 3}{(x - 1)(x -2)(x - 3)} \\ \\ = \frac{x - 1}{(x - 1)(x - 2)(x - 3)} \\ \\ = \frac{1}{(x - 2)(x - 3)}$