Answer:
(p∘q)(5) = 2
(q∘p)(5) = -1
Step-by-step explanation:
The composition of functions can be written a little differently, perhaps making it easier to understand.
(p∘q)(x) = p(q(x))
(p∘q)(5) = p(q(5)) = p(2·5 -5) = p(5) = 5 -3
(p∘q)(5) = 2
__
(q∘p)(5) = q(p(5)) = q(2) = 2·2 -5
(q∘p)(5) = -1
Answer:
560 cm
Step-by-step explanation:
Step 1: Find conversion
1 m = 100 cm
Step 2: Convert
5.6 m · 100 cm/m = 560 cm
Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is



So, area of square base is 100 sq. in.
Area of a triangle is



So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.




Therefore, the area of the pyramid is 180 sq. in.
<span>-15r + 3(2s - 4r)
=</span><span>-15r + 6s - 12r
= -27r + 6s
or
= 6s - 27r</span>
Answer:
The x and y intercept are (20,0)
Step-by-step explanation:
2x-4y=40—eqn1
-x+2y=-20—eqn2
Make x the subject of eqn2
-x=-20-2y
x=20+2y
plug this into eqn 1
2(20+2y)+4y=40
40+4y+4y=40
8y=40-40
y=0
plug y=0 into eqn2
-x+2(0)=-20
-x=-20
x=20