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ELEN [110]
3 years ago
12

What is the area of this figure? 4 cm 5cm 5cm Enter your answer in the box. cm? ​

Mathematics
1 answer:
Kruka [31]3 years ago
6 0
What’s the shape of it?
If it’s a rectangle 20
Bot something with more than 4 sides 100cm
You might be interested in
Write an equation of a line wit the given slope and y intercept
Orlov [11]

Answer:

Step-by-step explanation:

the standard equation of a line is in the form y=mx+b where m is the slope and b is the y intercept so if m = 1/4 and b = -3/4 you can just replace those spots giving you y=1/4x+-3/4

6 0
4 years ago
Helpppppppppppppppppppppppppppppppppppp
Vadim26 [7]

Answer:

m = - 1

Step-by-step explanation:

9m + 13 = 4

subtract 13 from both sides

9m = 4 - 13

9m = - 9

divide both sides by 9

m = - 1  (negative 1)

5 0
3 years ago
PLEASE ANSWER FOR BRAINLIEST!!
e-lub [12.9K]

Answer:

mFG = 67r ( Where r is the radius of the circle)

∠ECF = 67°

Step-by-step explanation:

i) m FG

Join CG

∠GCF=67°

(As FG=ED and equal chords subtend equal angle at center)

Now The length of the minor arc is given by the formula

m arc FG =

\frac {C}{2 \pi} \times 2 \pi r

∠C=67

m arc FG = \frac {67}{2 \pi} \times 2 \pi r

m arc FG = 67r

Where r is the radius of the circle.

2. ∠ECF = 67°

It is because of the rule which says that equal chords subtend equal angle at center

DE = EF

Hence ∠DCE = ∠ECF

7 0
3 years ago
Can someone please help me as soon as possible!
Elena-2011 [213]
Ed = 96 but switch the numbers
6 0
3 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

8 0
3 years ago
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