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3 years ago

MARKING BRAINLIEST please I’m desperate

Mathematics

2 answers:

telo118 [61]3 years ago

7 0

Answer:

The answer is (A) 24

Step-by-step explanation:

we can convert the 80 and the 3/10 into fractions then we can find the least common denominator of 10 and 80, it is 80 so 3 times 8 its 24 so the fraction should be 24/80 and there is you answer.

CaHeK987 [17]3 years ago

4 0

The answer is 24 times
3/10 x 80 = 24

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you have 96 feet of fencing to enclose a rectangular pen for your dog. the pen should be three times long as it is wide. write a

swat32

Answer:

length = 36 ft; width = 12 ft

Step-by-step explanation:

Let the width be x.

The length is 3x.

The perimeter is the sum of two lengths and two widths, and it equals 96 ft.

3x + 3x + x + x = 96

8x = 96

x = 12

Width = x = 12 ft

Length = 3x = 3(12 ft) = 36 ft

7 0

3 years ago

Read 2 more answers

Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh

Vedmedyk [2.9K]

Answer:

Increasing: $x$ and $x>1$ .

Decreasing: $-1$

Step-by-step explanation:

We have been given a function $f(x)=x^3-3x+4$ . We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

$f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)$

$f'(x)=3x^{3-1}-3+0$

$f'(x)=3x^{2}-3$

Let us equate derivative with 0 as find critical points as:

$0=3x^{2}-3$

$3x^{2}=3$

Divide both sides by 3:

$x^{2}=1$

Now we will take square-root of both sides as:

$\sqrt{x^{2}}=\pm\sqrt{1}$

$x=\pm 1$

$x=-1,1$

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

$f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9$