I hope this helps you

2x^2-4x+7=0 a=2 b=-4 c= 7

disctirminant =b^2-4ac

disctirminant =(-4)^2-4.2.7

disctirminant = 16-56= -40

x=-b+square root of disctirminant ÷2a

x=4+2square root of (-10)/4

x=2+square root of (-10)/2

x'=4 -2 square root of (-10)/4

x'=2 -square root of (-10)/2

6 0

2 years ago

What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?

shepuryov [24]

Refine $2(4z-3-1)$

$= 2(4z-4)$

Refine : $166 - 16 = 120$

therefore:

$2(z-4) = 120$

Divide both sides by 2 :

$\frac{2(z-4)}{2} = \frac{120}{2}$

$4z-4 = 60$

add 4 to both sides:

$4z-4+4 = 60+4$

$4z = 64$

Divide both sides by 4 :

$\frac{4z}{4} = \frac{64}{4}$

$z = 16$

hope this helps!

8 0

3 years ago

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