Answer:
The probability that at least 1 defective card is in the sample is 
Step-by-step explanation:
Here
N = 140
and n = 20
We will use the below given formula
P(at least 1 defective) = 1 - P( 0 defectives)
P( 0 defectives) =
He used 2 full can of paint 1/2 + 2/3 = 2
Y-y1=m(x-x1)
y-5=1/6(x-8)
y-5=1/6x-4/3
-1/6x+y=11/3
multiply both sides by -6
x-6y=-22
Step-by-step explanation:
if 9 boxes is 42.75 then 1 box is 4.75 dollars
so 13 boxes would be 13X3.75 which is 61.75$
if 9b=$42.75
1b=x
9bx=$42.75b
x=$42.75b÷9b
x=$4.75
The answer is <span>b.3x + 15 = 55 - x
</span>
x - Jill's present age
y - dad's present age
<span>In 5 years, Dad will be three times as old as his daughter Jill will be then:
y + 5 = 3(x + 5)
</span><span>The sum of their present ages is 50:
x + y = 50
We have the system of two equations now:
</span>y + 5 = 3(x + 5)
x + y = 50
Let's rearrange the second equation:
If: x + y = 50
Then: y = 50 - x
Now, substitute y from the second equation (y = 50 - x) into the first one:
y + 5 = 3(x + 5)
50 - x + 5 = 3(x + 5)
50 + 5 - x = 3*x + 3*5
55 - x = 3x + 15
Rearrange it a bit:
3x + 15 = 55 - x
Therefore, the correct choice is b.
