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AysviL [449]
3 years ago
6

3w - (7w + 12) = 2(w – 3)how do u do this step by step​

Mathematics
2 answers:
exis [7]3 years ago
3 0
3w-7w-12=2w-6

-4w-12=2w-6

-12=6w-6

-6=6w

w=-1
nata0808 [166]3 years ago
3 0

Answer:

w=-1

Step-by-step explanation:

3w-7w-12=2(w-3)

1) Combine alike terms:

-4w-12=2(w-3)

2) Use the Distributive property on the left side of the equation:

-4w+12=2w-6

3) Add a 6 to both sides:

-4w-6=2w

4) Add a 4w to both sides:

-6=6w

5) Divide both sides by 6:

w=-6/6

6) Simplify the fraction:

w=-1

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In fgh, mf = 50, mg= 60, and mh =70 which side of fgh is the shortest
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The shortest is 70 because they get smaller
5 0
3 years ago
Write an equation of the line containing the point (6,-4) and perpendicular to.the line y=-2x-3
igor_vitrenko [27]

Answer:

y=\frac{1}{2}x-7

Step-by-step explanation:

So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.

First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

m_1\cdot m_2=-1

Plug -2 for one of the slopes.

-2\cdot m_2=-1

Divide by -2 to find the slope of our line.

m_2=1/2

Thus, our line needs to have a slope of 1/2.

Now, let's use the point-slope form. The point-slope form is given by:

y-y_1=m(x-x_1)\\

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

y-(-4)=\frac{1}{2}(x-6)\\

Simplify and distribute:

y+4=\frac{1}{2} x-3

Subtract 4 from both sides:

y=\frac{1}{2}x-7

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.

5 0
3 years ago
Find the slope of 1,3 and 1,-2
svp [43]

Answer:

M=0

Step-by-step explanation:

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7 0
3 years ago
find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0
1 year ago
Which expression is equivalent to the given expression?
djverab [1.8K]

Answer:

a. 5q+5q+5

Step-by-step explanation:

5q+5q=10q

10q+5 is equivalent to 10q+5

8 0
3 years ago
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