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Darina [25.2K]
3 years ago
7

Drag each interval to a box to show if the function shown is increasing, decreasing, or neither over that interval.

Mathematics
1 answer:
ad-work [718]3 years ago
4 0

Answer:

First, we need to know when the function is increasing, and when is decreasing.

When a function is increasing, it's because to higher <em>x-values </em>belong higher <em>y-values. </em>On the other hand, a function is decreasing when to higher <em>x-values </em>belong lower <em>y-values. </em>The effect in the graph will be a upwards direction of the function when is increasing, and a downwards direction when is decreasing.

So, according to the given graph, we see that between 0 and 4 is increasing, the higher x-values are, higher y-values are. Between 4 and 6 is decreasing, is downwards. Between 6 and 8 is increasing. Between 8 and 10 is decreasing. In finally, between 10 and 14 is neither decreasing or increasing, it remains horizontal.

All these interpretations we can expressed using math language, specifically inequalities:

  • 0 < x < 4: increasing.
  • 4 < x < 6: decreasing.
  • 6 < x < 8: increasing.
  • 8 < x < 10: decreasing.
  • 10 < x < 14: neither increasing or decreasing.

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5 0
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Answer:

4

Step-by-step explanation:

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y = 4*1.5 = 6

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3 0
2 years ago
THIS IS IMPORTANT!!What is the apparent solution to the system of equations?
Ann [662]
Make each equation equal to each other, then solve for x.
-x+2=4x+7
-x-4x=7-2
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X=-1
Sub x into one if the y formulas to find y
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See my picture for how to graph the points.
Hope this helps!

8 0
3 years ago
Please I need help with this and show your steps
Lorico [155]

Answer:

-30/15 or -2

Step-by-step explanation:

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(Find GCF)(GCF = 15)(5 times 3)

30/15 (10/5 times 3)

60/15 (12/3 times 5)

30/15 - 60/15 = -30/15 --> -2(simplified to 2)

7 0
3 years ago
Read 2 more answers
Please answer this I will give u​
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Answer:

Step-by-step explanation:

The 3 angles must add up to 180. So

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12x = 180

x = 15

Plug this into all the angles and you have your answers

5 0
3 years ago
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