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Darina [25.2K]
4 years ago
7

Drag each interval to a box to show if the function shown is increasing, decreasing, or neither over that interval.

Mathematics
1 answer:
ad-work [718]4 years ago
4 0

Answer:

First, we need to know when the function is increasing, and when is decreasing.

When a function is increasing, it's because to higher <em>x-values </em>belong higher <em>y-values. </em>On the other hand, a function is decreasing when to higher <em>x-values </em>belong lower <em>y-values. </em>The effect in the graph will be a upwards direction of the function when is increasing, and a downwards direction when is decreasing.

So, according to the given graph, we see that between 0 and 4 is increasing, the higher x-values are, higher y-values are. Between 4 and 6 is decreasing, is downwards. Between 6 and 8 is increasing. Between 8 and 10 is decreasing. In finally, between 10 and 14 is neither decreasing or increasing, it remains horizontal.

All these interpretations we can expressed using math language, specifically inequalities:

  • 0 < x < 4: increasing.
  • 4 < x < 6: decreasing.
  • 6 < x < 8: increasing.
  • 8 < x < 10: decreasing.
  • 10 < x < 14: neither increasing or decreasing.

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\tt B)\;93^o

Step-by-step explanation:

\tt 2(19x+1)+(19x+1)+15x=360

\tt 38x+2+19x-2+15x=360

\tt 38x+19x+15x+2-2=360 (Add similar elements)

\tt 72x+2-2=360 (2-2=0)

\tt 72x=360

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2 years ago
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The interquartile range of the data set is 8

<h3>How to solve for the interquartile range</h3>

To do this we have to arrange in ascending order

= 8,9,9,9,10,11,13,15,17,18,22

Q2 = The median of the data is 11.

We have to find the median of the half before 11 and the median of the half after 11.

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The interquartile range of the data set is 8

Read more on interquartile range here:

brainly.com/question/12967898

#SPJ1

Correct question

Study the following data set.

{8,15,9,18,9,17,22,10,11,9,13}

What is the interquartile range of the data set?

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