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mash [69]
3 years ago
9

How can I solve that

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
B and for question 3 b
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2 years ago
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Elanso [62]

Answer:

Step-by-step explanation:

8 0
2 years ago
The answer to the question below is 8/15 right?
ioda
When you have something like this, to simplify the exponent you multiply them together, so the exponent is 1/3 x 1/5. 
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3 0
3 years ago
Read 2 more answers
write an equation in slope intercept form of the line that passes through the points. (-4, 2), (1, -1)
viva [34]

Answer:Y = 3\5x -2\5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
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