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Arlecino [84]
3 years ago
15

What is 97/50 as a decimal

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0
97/50
divide 97 by 50 to get 1.94
or multiply 97/50 by 2 to get 194 then divide by 100 
to get 1.94
FinnZ [79.3K]3 years ago
4 0
97/50 would be multipled by 2 to get 0.196. You multiply by 2 to make it easier
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C=30m+50 and c=20m+100<br> solve for m pls help
Sholpan [36]

Answer:

m=5

Step-by-step explanation:

c=30m+50

c=20m+100

substitute

20m+100=30m+50

like terms

100-50=30m-20m

50=10m

m=5

6 0
3 years ago
Read 2 more answers
A) Draw the graph of y= 4x - 1 on the grid
UkoKoshka [18]

9514 1404 393

Answer:

  see attached for a graph

  x = 0.5 when y = 1

Step-by-step explanation:

The graph has a y-intercept of -1, which is halfway between 0 and -2. It goes up 4 units (2 vertical grid spaces) for 1 unit to the right (1 horizontal grid space). It seems to cross y = 1 at about x = 1/2.

x = 1/2 when y = 1.

4 0
2 years ago
In previous months, you ordered 80 boxes of pens per month. This month, you want to decrease the number of boxes of pens you ord
Lapatulllka [165]
80(0.40)=32
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3 0
2 years ago
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Im confused can somebody help me please
ivann1987 [24]

well, we know the piece-wise function is f(x)= \begin{cases} 7x+10&x < 0\\\\ 7x+20&x\geqslant 0 \end{cases}

hmmm so what's f(-1), namely what is f(x) when x = -1?

well, when x = -1, hmm -1 is less than 0, so the subfunction that applies to that will be when "x" is less than 0, namely the part of 7x + 10, so we can say

f(-1) = 7(-1) + 10

f(-1) = 3

so hmm what's f(0) or namely, what's f(x) when x = 0?

well, what subfunction applies when x = 0? well, it has to be the subfunction with "x greater or <u>equals</u> to 0", x ⩾ 0, so then is 7x + 20

f(0) = 7(0) + 20

f(0) = 20.

6 0
2 years ago
Simplify this question
vladimir1956 [14]

\frac{8 -  \sqrt{ - 36} }{2}  \\  =  \frac{8 -  \sqrt{ 2 \times \: 2 \times  3  \times  - 3} }{2}  \\  =  \frac{8 -2 \sqrt{ - 9}  }{2}  \\  =  \frac{2(4 -  \sqrt{ - 9} )}{2}  \\  = 4 -  \sqrt{ - 9}

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
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