In exponent multiplication, When the bases are the same you ADD the power so it is n^7
To solve this first find the area of each of the white shapes inside the rectangle
The formula for the area of a circle is:
A = πr²
In this case we know that the radius is 2
Plug what you know into the area of a circle formula:
A = π2²
A = π4
A = 4π
A ≈ 12.57
The formula for the area of a square is:
A = Length x Height
In this case we know that both length and height are 3
Plug what you know into the formula for area of a square:
A = 3 x 3
A = 9
To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):
12.57 + 9 ≈ 21.57
To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.
The formula for the area of a rectangle is:
A = Length x Height
The length is 10 and the height is 7
A = 10 x 7
A = 70
Shaded region:
70 - 21.57 = 48.43
Unshaded region: 21.57
Total area of surrounding rectangle: 70
Shaded region: 48.43
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL = /2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN
Answer:
1064 m²
Step-by-step explanation:
The surface area of the prism can be gotten by saying
14 * 14 + 14 * 14 + 14 * 24 =
196 + 196 + 336 =
728 m²
Again, after dealing with the rectangle, we then face the triangle.
Area of triangle is
1/2 * 14 * 24
There are 2 triangles so this makes it
2 * 1/2 * 14 * 24 =
336
The surface area is finally
336 + 728 = 1064 m²
Surface area of the triangular prism has been calculated to be 1064 m²
Step-by-step explanation:
right now but I have no idea how much that would have to be in the same place as last week and he said it would be a lot of people are coming to see you and the girls are doing well and
