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jeka57 [31]
2 years ago
5

hiii I don't need the answer but do you know what this is about and may you please explain? thank youuu ​

Mathematics
1 answer:
frez [133]2 years ago
4 0

Answer:

If you would want to download it you may or you don't want it it's your choice

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The difference of two numbers, a and b, is 21. The difference of 5 times a and two times b is 18. What are the values of a and b
PSYCHO15rus [73]
A-b=21
5a-2b=18

We can use substitution here. Take the first equation and solve for A. (Picking this one because it's easy)

a = 21+b

Plugin to the second equation:5(21+b)-2b=18
Simplify: 105 + 5b - 2b = 18
Simplify: 105 + 3b = 18
Subtract both sides: 3b = 18-105
Simplify: 3b = -87
Divide: b = -29

Plug back into the first: a=21+b
a = 21 - 29
a = -8

Option D

6 0
3 years ago
Help me please thank you
LuckyWell [14K]

Answer:

$13.70

Step-by-step explanation:

$59.60 - $4.80 = $54.80

$54.80 / 4 = $13.70

3 0
2 years ago
Read 2 more answers
Someone please help me if you can!
Dovator [93]
I love these!

Okay, so this is a right angle. That means it is 90 degrees.

So far we know that on side of the angle is 47 degrees.

To get the other angle we will just subtract 90 - 47 = 43
8 0
3 years ago
Read 2 more answers
The length of a rectangle is twice it’s width.The perimeter of the rectangle in 162 inches.How long is the rectangle?
Artist 52 [7]
The perimeter of a rectangle is all sides added  up, so length + length + width + width.

L = length

W = width

then the perimeter is L+L+W+W, or 2L + 2W, or 2(L+W).

\bf \textit{perimeter of a rectangle}\\\\
P=2(L+W)~~
\begin{cases}
P=162\\
L=\stackrel{\textit{twice W}}{2W}
\end{cases}\implies 162=2(2W+W)
\\\\\\
\cfrac{162}{2}=3W\implies 81=3W\implies \cfrac{81}{3}=W\implies 27=W

what's the length?  well, is just 2(27).
6 0
3 years ago
I need to simplify this
Korvikt [17]
Hi there!

3 \sqrt{54} + 2 \sqrt{24} =
First we split up the square root into two parts.

3 \times \sqrt{9} \times \sqrt{6} + 2 \times \sqrt{4} \times \sqrt{6} =
Now we calculate the value of the square roots which have an integer as a solution

3 \times 3 \times \sqrt{6} + 2 \times 2 \times \sqrt{6} =
Multiplying the integers gives us our next step.

9 \sqrt{6} + 4 \sqrt{6} =
And finally we add up the roots.

13 \sqrt{6}
3 0
3 years ago
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