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lilavasa [31]
3 years ago
7

Find the area of this irregular polygon.

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:

970m^{2}

Step-by-step explanation:

This polygon can be divided in two figures: one is a triangle, an the other one is a square.

We'll begin calculating the triangle's area, using the following formula:

At= \frac{b.h}{2}

Where:

H= height = 30 m

B = 9 m + 9 m + 20 m = 38 m

As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.

At= \frac{38 m .30 m}{2}

At= \frac{1140 m^{2} }{2}

At= 570 m^{2}

Now we are going to calculate the square's area, that is much more simple:

As= L^{2}

Where:

L=20 m

As= (20 m)^{2} = 400m^{2}

To know the whole figure's area, we add up both areas:

A = At+As = 570m^{2} +400m^{2}=970m^{2}

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