Question

Find the area of this irregular polygon.

Answer 1

Answer:

970m^{2}

Step-by-step explanation:

This polygon can be divided in two figures: one is a triangle, an the other one is a square.

We'll begin calculating the triangle's area, using the following formula:

$At= \frac{b.h}{2}$

Where:

$H= height = 30 m$

$B = 9 m + 9 m + 20 m = 38 m$

As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.

$At= \frac{38 m .30 m}{2}$

$At= \frac{1140 m^{2} }{2}$

$At= 570 m^{2}$

Now we are going to calculate the square's area, that is much more simple:

$As= L^{2}$

Where:

$L=20 m$

$As= (20 m)^{2} = 400m^{2}$

To know the whole figure's area, we add up both areas:

$A = At+As = 570m^{2} +400m^{2}=970m^{2}$