Answer:
Oliver completed his training work in 50.25 hours
Step-by-step explanation:
we know that
1 day= 24 hours
1 hour=60 minutes
we have
2 days, 2 h, and 15 min
<u><em>Convert days to hours</em></u>
2 days=2(24)=48 hours
<u><em>Convert minutes to hour</em></u>
15 min=15(1/60)=1/4=0.25 h
so
2 days, 2 h, and 15 min=(48)+(2)+(0.25)=50.25 h
therefore
Oliver completed his training work in 50.25 hours
I’m going to say the top one it seems like that would be correct
<h3>
Answer: Choice H) 2</h3>
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Explanation:
Recall that the pythagorean trig identity is ![\sin^2 x + \cos^2x = 1](https://tex.z-dn.net/?f=%5Csin%5E2%20x%20%2B%20%5Ccos%5E2x%20%3D%201)
If we were to isolate sine, then,
![\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\](https://tex.z-dn.net/?f=%5Csin%5E2%20x%20%2B%20%5Ccos%5E2x%20%3D%201%5C%5C%5C%5C%5Csin%5E2%20x%20%3D%201-%5Ccos%5E2x%5C%5C%5C%5C%5Csin%20x%20%3D%20%5Csqrt%7B1-%5Ccos%5E2x%7D%5C%5C%5C%5C)
We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations,
Cosine is also positive in this quadrant.
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So,
![\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B1-%5Ccos%5E2x%7D%7D%7B%5Csin%20x%7D%2B%5Cfrac%7B%5Csqrt%7B1-%5Csin%5E2x%7D%7D%7B%5Ccos%20x%7D%5C%5C%5C%5C%5Cfrac%7B%5Csin%20x%7D%7B%5Csin%20x%7D%2B%5Cfrac%7B%5Ccos%20x%7D%7B%5Ccos%20x%7D%5C%5C%5C%5C1%2B1%5C%5C%5C%5C2)
Therefore,
![\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B1-%5Ccos%5E2x%7D%7D%7B%5Csin%20x%7D%2B%5Cfrac%7B%5Csqrt%7B1-%5Csin%5E2x%7D%7D%7B%5Ccos%20x%7D%3D2)
is an identity as long as 0 < x < pi/2
Answer: 3• D 4• B (why does this require me to put 20 characters) anyway this is my guess