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Ronch [10]
4 years ago
8

$2.99 toy ; 30% discount

Mathematics
1 answer:
Setler79 [48]4 years ago
5 0
If a toy that costs $2.99 is at a 30% discount then you first need to make 30% a decimal.

30% = .3

Now multiply $2.99 by .3 to find the discount which is .897

Since .897 has a thousandths place we need to round that which would make it 90 cents.

Now we know there is a 90 cent discount on a $2.99 toy.

take $2.99 - 90 cents = $2.09

The toy costs $2.09 after a 30% discount
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Solve using quadratic equations (x+3)^2=25
Mandarinka [93]

Answer:

x=2 or x=−8

Step-by-step explanation:

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3 years ago
If x+y=16 and x-y=-2, what is the value of xy?
Fantom [35]

Answer:

Y=7 and

X=9

Step-by-step explanation:

X+Y=16

X=2+Y

2+Y+Y=16

2+2Y=16

2Y=16-2

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4 0
3 years ago
The original price of a computer was reduced by 225 dollars. The new discounter price is 1274 dollars.
Svetlanka [38]

Answer:

1499

Step-by-step explanation:

Given that :

New discounted price = 1274

Let original price = p

Reduction in original price = 225

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8 0
3 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. Supp
Trava [24]

Answer:

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

Step-by-step explanation:

As the test is targeted to 18-to-29-year-old adults using  social media, we want to know the probability that a randomly selected adult uses social media and belong to the study group.

To achieve this, we have this data:

- 36% of all adults do not use social media

- 75% of all adults are >30 years old.

- The percentage of population that is <em>either</em> 18-29 years old <em>or</em> uses social media is 66.7%

Using the last data we have that

P(social\,media=yes\, or\,18-29=yes)=P(social\,media=yes)+P(18-29=yes)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=(1-0.36)+(1-0.75)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=0.64+0.25-P(social\,media=yes\, \&\,18-29=yes)\\\\P(social\,media=yes\, \&\,18-29=yes)=0.64+0.25-0.667=0.223

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

8 0
3 years ago
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