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iogann1982 [59]
3 years ago
9

How to simplify 24yz^5/32y^2z

Mathematics
1 answer:
Maurinko [17]3 years ago
8 0
24y*z^5/32y^2*z

24/32 = 3/4
y/y^2 = 1/y
z^5/z = z^4/1

Soo now that they are all simplified the answer is 3z^4/4y
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Answer:

Take deep breaths and focus, don't be afraid to ask for help.

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3 years ago
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in a round robin tennis tournament involving 7 players, each player will play every other player twice. How many total matches w
baherus [9]
Total number of ways to make a pair:

The first player can be any one of 7 .  For each of those . . .
The opponent can be any one of the remaining 6 .

Total ways to make a pair  =  7 x 6 = 42 ways .

BUT ... every pair can be made in two ways ...  A vs B  or  B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.

If every pair plays 2 matches, then  (21 x 2) = <em><u>42 total matches</u></em> will be played.


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8 0
3 years ago
Will give brainliest!!! The MTC Theater holds 250 people, and last night’s performance sold out! Students under the age of 16 pa
MakcuM [25]
60 children tickets and 190 adult tickets were sold.

Step-by-step explanation:

Let the no. of adult tickets sold be 'a'

Let the no. of children tickets sold be 'c'

Total tickets sold = 250

Cost of 1 children ticket = $2.5

Cost of 1 adult ticket = $4

Total money collected= $910

Given that,
a + c = 250
a = 250 - c
4a + 2.5c = 910

Substitute a value
4(250 - c) + 2.5c = 910
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1000 - 1.5c = 910
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c = 60
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4 0
2 years ago
Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
Kenneth bought a new roll of tape. There were 59.6 yards of tape on the roll. Then Kenneth used 4 yards of the tape to make a co
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Answer:

55.6 yards

Step-by-step explanation:

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