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ad-work [718]
3 years ago
13

A) Graph the following two lines on the same rectangular coordinate system. Show all your working. You need to use the slope-int

ercept method.
Graph A: 3x+2y=12 Graph B: 4x-y=5
B) Mark the point intersection of the two graphs M, and give coordinates.
C) What is the difference in units between the Y-coordinates of Graph A and Y-coordinates of Graph B?
E) Draw the graph x-=6 on the same set of axes. At which point does this line cut Graph A?

Mathematics
1 answer:
Oksanka [162]3 years ago
8 0
Graph a.

3x+2y=12
-3x -3x

2y=-3x+12
2/2y=(3x+12)/2

y=-1.5x+6

graph b.

4x-y=5
+y +y

4x=y+5
-5 -5

4x-5=y

c) 11 units is the difference between y-coordinates of graph a and y-coordinates of graph b.

e) at (6,-3) x=6 cuts into graph a

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Answer: 659 13/18 yd^2 or 659.7yd^2                ^ =squared

Step-by-step explanation:

This is the answer because you have 6 sides of this prism. That means 3 sides are parallel to the sides across from them. So, 12 1/2 yd by 8 1/3 yd is 104 1/6, then multiply by 2. That equals 208 1/3. Then, 10 5/6 yd by 8 1/3 yd is 90 5/18. then times by 2. That equals 180 5/9. Next, 10 5/6yd by 12 1/2 is 135 and 5/12. then times by 2 and that is 270 5/6yd.

add 208 1/3 + 180 5/9 + 270 5/6

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3 years ago
Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot
klemol [59]

Answer: The distance around the lot is given by

4\frac{1}{20}\ miles

Step-by-step explanation:

Since we have given that

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Width of rectangular lot is given by

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We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles

Hence, the distance around the lot is given by

4\frac{1}{20}\ miles


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