Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
y=5, x=7 because if 3x5=15 then 15-7=8 dont report me if i do get this wrong
Answer:
1/2
Step-by-step explanation:
The answer is 1/2 because the fraction 4/8 can be simplified into 1/2 because they are the same.
Answer: He will practice both on every 15 days.
Step-by-step explanation:
Given: Jaquan practices soccer every 3 days.
He practices basketball every 5 days Jaquan practiced both today.
The number of days until he practices both = Least common multiple of 3 and 5
= 3 x 5 [Both are primes]
= 15
Hence, he will practice both on every 15 days.
- Least common multiple of two numbers p and q is the smallest number that is divisible by both p and q.
Answer:
c) if x=2, then 4x=8
Step-by-step explanation: