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andrezito [222]
4 years ago
12

|x+y−z| , if x=−5; y=−2; z=−4

Mathematics
1 answer:
iren2701 [21]4 years ago
5 0
<span>|x + y − z|

Plug in x, y, and z.

</span>|(-5) + (-2) - (-4)|

Solve.

|-3|

The absolute value symbols, |, mean that the negatives in the number don't matter. It just means how far away from 0 the number is.

So, |-3| = 3.

The answer is 3.
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Kim purchased a desktop computer at Best Buy for 20% off the original price. If the original price of the desktop is $1500, how
Arturiano [62]

Answer:

So for this sale, you'll save $300.00 on this item.

This means, the cost of the item to you is

$1500 - $300.00 = $1200.00.

3 0
3 years ago
During the first part of a​ trip, a canoeist travels 18 miles at a certain speed. the canoeist travels 4 miles on the second par
storchak [24]
We can set it up like this, where <em>s </em>is the speed of the canoeist:

\frac{18}{s} + \frac{4}{s-5} = 3

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):

s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s

If we rearrange this, we can turn it into a quadratic equation and factor:

18s - 90+4s=3 s^{2} -15s \\ 22s-90=3 s^{2} -15s \\ 3 s^{2} -37s+90=0 \\ (3s-10)(s-9)=0 \\ s= \frac{10}{3} ,9

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater."  We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

9-5 = 4

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
5 0
4 years ago
Why did the scientsit creat an exact duplicate of himself
MissTica
Rly, this is the stupidest question to live on earth
7 0
3 years ago
Read 2 more answers
I dont know how to do this
arlik [135]

Answer:

steps below

Step-by-step explanation:

post here 16 and 17, should be able to do 18 and 19 yourself

16.

y=-8 for x≤-6

y=-1/4 x + 2 for -4≤x≤4

y=4 for x>4

17.

y=-x-4 for x<-3

y=x+1 for -3≤x≤1

y=-6 for x>4

4 0
3 years ago
Heights of men on a basketball team have a bell shaped distribution with a mean of 173 cm and a standard deviation of 8 cm using
ASHA 777 [7]
I have a similar problem here with a slightly different given. 

Heights of men on a baseball team have a bell shaped distrubtion with a mean of 172cm and a standard deviation of 7cm. Using that is the empirical rule, what is the approximate percentage of the men between the following values? 
a) 165 cm and 179cm 
<span>b) 151cm and 193cm
</span>
The solution is:

 <span>a. (165-172)/7 = -1, (179-172)/7 = 1, % by empirical rule = 68% 

b. (151-172)/7 = -3, (193-172)/7 = 3, % by empirical rule = 99.7%
</span>
I hope that by examining the solution for this problem, it could help you  answer your problem on your own.
3 0
4 years ago
Read 2 more answers
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