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Rom4ik [11]
3 years ago
8

Identify the volume of a sphere with surface area 144π m2. Give your answer in terms of π.

Mathematics
1 answer:
anygoal [31]3 years ago
4 0

\bf \textit{surface area of a sphere}\\\\ SA = 4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} SA=144\pi \end{cases}\implies 144\pi =4\pi r^2\implies \cfrac{144\pi }{4\pi }=r^2 \\\\\\ 36=r^2\implies \sqrt{36}=r\implies \underline{6}=r \\\\[-0.35em] ~\dotfill\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad \qquad \implies V=\cfrac{4\pi (\underline{6})^3}{3}\implies V=288\pi

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A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
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Answer:

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Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

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<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

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Step-by-step explanation:

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A pumpkin is launched directly upwards at 72 feet per second from a platform 24 feet high. The pumpkins height, h, at time t sec
STALIN [3.7K]

Answer: Maximum height =  105 feet

And, It takes 9/4 seconds to reach that point.

Step-by-step explanation:

Here the given function that shows the height of the pumpkin,

h(t) = -16t^2 + 72t + 24 --------(1)

Where t is the time in second.

Differentiating equation (1) with respect to t,

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Again differentiating above equation with respect to t,

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For maximum or minimum,    h'(t) = 0

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Therefore, At t = 9/4 seconds, h(t) is maximum,

And, the maximum value is,

h(\frac{9}{4} ) = -16(\frac{9}{4})^2 + 72(\frac{9}{4}) + 24

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Therefore, the maximum height of the pumpkin is 105 feet at 9/4 seconds

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