We can’t see the statements
Answer:
-- Domain
-- Range
It is a function
Step-by-step explanation:
Given


Required
State the domain and range
Determine if the relation is a function
From the question, we have the domain and range as:
-- Domain
-- Range
Next, is to determine if the relation is a function or not.
Yes, it is a function.
The number of elements in the domain is 4
The number of elements in the range is 3
<em>When the domain has more elements than the range, this is called a many-to-one function, and it is a valid type of function.</em>
Answer: Option C

Step-by-step explanation:
The graph shows a radical function of the form 
Where n is a positive number.
For this type of function, if the coefficient
then then when x tends to
f(x) tends to
and when x tends to
then f(x) tends to
.
Notice in the graph that as x increases then f(x) also increases and as x decreases f(x) also decreases.
This indicates that the coefficient 
Since

is negative, it doesn't have any real roots.
Step-by-step explanation:

- Length of MN ( Base ) = 8
- Length of NL ( Hypotenuse ) = 10

- Length of LM ( Perpendicular )


⤑ 
⤑ 
⤑ 
⤑ 
⤑ 

Hope I helped ! ツ
Have a wonderful day / night ! ♡
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