PLEASE HELP if both integers are negative then their sum is

Mathematics

2 answers:

pav-90 [236]2 years ago

8 0

Answer:

from what I know it should be always negative

Step-by-step explanation:

ryzh [129]2 years ago

7 0

always positive! adding two negative integers will always result in a positive sum

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Given f(x)=3x^2+5 and g(x)=x−2 . What is (fg)(x) ? 3x^2−x+7 3x^3−6x2+5x−10 −3x^2+x−7 3x^3−10

wolverine [178]

For this case we have that by definition:

$(fg) (x) = f (x) * g (x)$

So:

$(fg) (x) = (3x ^ 2 + 5) (x-2)$

We apply distributive property that states that:

$(a + b) (c + d) = ac + ad + bc + bd$

In addition, we take into account that:

$+ * - = -$

$(fg) (x) = 3x ^ 3-6x ^ 2 + 5x-10$

Answer:

$3x ^ 3-6x ^ 2 + 5x-10$

Option B

6 0

2 years ago

Read 2 more answers

Answer the question with explanation;

PSYCHO15rus [73]

Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

$\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0$

Therefore, by the series divergence test, the series $\sum_{n=1}^\infty\frac{n^2}{(n+1)^2}$ diverges.

EDIT: To VectorFundament120, if $(x_n)_{n\in\mathbb N}$ is a sequence, both $\lim x_n$ and $\lim_{n\to\infty}x_n$ are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.