Given :
A water well rig has dug to a height , H = 60 feet after one full day of continuous use .
To Find :
If the height is currently 143.6 feet how time it been running .
Solution :
It is given that height after 24 hours of use is 60 feet .
So , height loose in 1 hours is :

Now , time taken to cover a height of 143.6 feet is :

Therefore , time taken is 57.44 hours .
Hence , this is the required solution .
The answer would be 1/4 :)
Answer:
see below
Step-by-step explanation:
by rewriting the function we can see that it has a minimum at
![y=7x^2+7x-7\Rightarrow y=7(x^2+x-1)\Rightarrow y=7[(x+\frac{1}{2})^2-\frac{1}{4}-1]\Rightarrow](https://tex.z-dn.net/?f=y%3D7x%5E2%2B7x-7%5CRightarrow%20y%3D7%28x%5E2%2Bx-1%29%5CRightarrow%20y%3D7%5B%28x%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2-%5Cfrac%7B1%7D%7B4%7D-1%5D%5CRightarrow)
![y=7[(x+\frac{1}{2})^2-\frac{5}{4}]\Rightarrow minimum \ (-\frac{1}{2}, -\frac{35}{4})](https://tex.z-dn.net/?f=y%3D7%5B%28x%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2-%5Cfrac%7B5%7D%7B4%7D%5D%5CRightarrow%20minimum%20%5C%20%28-%5Cfrac%7B1%7D%7B2%7D%2C%20-%5Cfrac%7B35%7D%7B4%7D%29)
bye.