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Marianna [84]
3 years ago
8

Mike's plant grew 3 inches last week. Lauren's plant grew 2 1/2 times this amount. how many inches did Lauren's plant grow last

week?
Mathematics
2 answers:
Helen [10]3 years ago
5 0
I believe 7 1/2 inches more, hope this helps! Can I get a brainliest? I need them BADLY!
soldier1979 [14.2K]3 years ago
3 0
Mike's plant plant height grew by 3 in
Lauren's grew 2 1/2 times of 3 in

So, 2 1/2 times of 3 in
= 2 1/2 x 3
= 5/2 x 3
= 15/2 = 7 1/2 inches

Hope This Helps You;
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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

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2 years ago
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