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sdas [7]
3 years ago
15

What is the slope of a line that is perpendicular to the line v=3/4 x-6

Mathematics
2 answers:
defon3 years ago
6 0
U flip the regular slope and change it to negative since its perpendicular so it would be -4/3
-Dominant- [34]3 years ago
4 0
Y = 3/4x - 6....the slope of this line is 3/4. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of a number, u flip the number and change the sign. So our perpendicular line will have a slope of -4/3 (see how I flipped 3/4 making it 4/3....and then change the sign...making it -4/3)

so the slope of the perpendicular line is -4/3
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Please help me solve this! <br> Will give Brainliest!<br> Please help quickly!
dangina [55]

Answer:

y = 6.5

Step-by-step explanation:

Using a ratio

10           13

-----    = -----------

10+5      13+y

10           13

-----    = -----------

15        13+y

Using cross products

10(13+y) = 13*15

10(13+y) = 195

130+10y = 195

Subtract 130 from each side

10y = 65

Divide by 10

y = 65/10

y = 6.5

7 0
3 years ago
No guess please explain
kirill115 [55]
No, is not a function because for the same value of X it has two different values of y, that’s not the definition of function.

7 0
3 years ago
What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?
Nookie1986 [14]

Answer:

B) 2n + 1

Step-by-step explanation:

Each term increases by 2 units so the common difference is 2. Then plug in 1 into the equations that have a slope of 2 and see if you get 3 out. You do for 2n + 1.

7 0
4 years ago
Put these in order of size<br> smallest first b-day 0.3 75% 4/5
S_A_V [24]
The answer is 0.3 75 4/5
6 0
4 years ago
Read 2 more answers
Find the coordinates of the midpoint (M) of PQ. ​
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

Givens

P is (2,8)

Q is (-6,-6)

Equation

Midpoint = (x1 + x2)/2,(y1 + y2)/2

Solution

x1 = - 6

x2 = 2

y1 = -6

y2 = 8

M = (-6 + 2)/2, (-6+8)/2

M = -4/2, 2/2

M = -2 , 1

Just to make sure that you know that the answer is reasonable, I've put the midpoint (-2,1) on a graph with the two endpoints. You could print the points out and check it with a ruler.

4 0
3 years ago
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