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cluponka [151]
3 years ago
14

Please help me solve this! Will give Brainliest! Please help quickly!

Mathematics
1 answer:
dangina [55]3 years ago
7 0

Answer:

y = 6.5

Step-by-step explanation:

Using a ratio

10           13

-----    = -----------

10+5      13+y

10           13

-----    = -----------

15        13+y

Using cross products

10(13+y) = 13*15

10(13+y) = 195

130+10y = 195

Subtract 130 from each side

10y = 65

Divide by 10

y = 65/10

y = 6.5

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The cost of a pen at the office supply store is $2.65. The school store sells the pen for $3.45. How much does the school store
Julli [10]
The pen is what ever when you subtract them
3 0
3 years ago
The area of a square is 32 square inches. Which equation best represents the length of one side of the square
neonofarm [45]

Answer:

A Variable that you feel comfortable with whether it is A,B,C, or X,Y,Z.

I choose S

Step-by-step explanation:

The formula for Area of A Square is-

A= X*X

A: meaning area

X: meaning sides

All your doing is multiplying side by side, Not all sides, Just 2 sides

8 0
3 years ago
A water tank is in the shape of a right circular cone as shown above. The diameter of the cone is 10 feet, and the height is 15
Vsevolod [243]

Answer:

The rate at which the height of the water tank is changing is approximately 0.4244 ft/hour

Step-by-step explanation:

The given parameters are;

The diameter of the cone = 10 feet

The height of the cone = 15 feet

The rate at which water is leaking from the tank, (dV/dt) = 12 ft³/h

The volume of water in the tank = 27·π cubic feet

The volume V of a right circular cone with radius r and height h = 1/3×π×r²×h

The rate of change of the volume, dV, with time dt is given as follows;

The radius of the cone when the volume of the water in the tank is 27·π cubic feet is given as follows;

1/3×π×r²×h = 27·π ft³

The ratio of the height to the radius of the cone is h/r = 15/5 = 3

h/r = 3

∴ r =h/3

The volume of the cone, V = 1/3×π×r²×h = 1/3×π×(h/3)²×h = 1/27×π×h³ =  h³/27×π

dV/dt = dV/dh × dh/dt

Which gives;

12 = d(h³/27×π)/dh × dh/dt = π×h²/9 × dh/dt

dh/dt = 12/(π×h²/9)

At 27·π ft³ = 1/27×π×h³ ft³, we have;

27 = 1/27×h³

27² = h³

h = ∛27² = 9

∴ dh/dt = 12/(π×h²/9) = 12/(π×9²/9) = 12/(π×9) = 4/(3·π) ≈ 0.4244 ft/hour

The rate at which the height of the water tank is changing ≈ 0.4244 ft/hour.

6 0
3 years ago
Evaluate 5x³ + 2 for x = -1.<br> 0 -3<br> 04<br> 06<br> 0-7
zysi [14]

Answer:

-3

Step-by-step explanation:

5x³ + 2 , when x = -1

5(-1)³ + 2

= -5 + 2

= -3

6 0
2 years ago
Read 2 more answers
I been so lost and confused on this ;( help?
viva [34]
2x - 5y = 9
2x -9 = 5y
(2x -9) /5 = y

x= -1
(2(-1) -9)/5 =y
(-2 -9) / 5 = y
-11/5 = y

x=0
(0-9)/5 = y
-9/5 = y

x=1
(2(1) - 9) /5 = y
-7/5 = y
5 0
3 years ago
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