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Elina [12.6K]
4 years ago
8

Which of the following represents a function?

Mathematics
1 answer:
vichka [17]4 years ago
6 0
The 3rd one on top is correct
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A warren of rabbits has a population of 350. The population is increasing at a rate of 3% per year. How can you write an exponen
koban [17]

Answer:

P(t) = 350e^{0.0025t}

Step-by-step explanation:

Exponential growth function:

The exponential growth function for a population, after t years, is given by:

P(t) = P(0)e^{rt}

In which P(0) is the initial population and r is the growth rate.

A warren of rabbits has a population of 350. The population is increasing at a rate of 3% per year.

This means that P(0) = 350, r = 0.03

So

P(t) = P(0)e^{rt}

P(t) = 350e^{0.03t}

How can you write an exponential growth function to find the monthly growth rate?

Monthly growth rate means that the time is divided by 12(as one year has 12 months), so the equation will be:

P(t) = 350e^{0.03\frac{t}{12}}

P(t) = 350e^{0.0025t}

6 0
3 years ago
PLEASE HELP 80 POINTS DUE SOON! GIVING BRAINLIEST
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Answer:

Ok ill help

Step-by-step explanation:

by getting the points

4 0
3 years ago
Read 2 more answers
Describe a situation in your life when you need to know how to find a starting time
taurus [48]
Running laps and timing them

3 0
4 years ago
He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

A(t)=136(1.123)^{4t}

Answer:

   Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

  • A(t)=136(1.123)^{4t}

  • rate=(1.123)^{4t}=(1.123)^4=1.590

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590

6 0
3 years ago
Six time a number is greater then 20 more then that number
denpristay [2]
6n > n + 20. Hope it helps!
5 0
3 years ago
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