Answer:
pollen is important in fertilization because pollen carries male gamete and it helps in transportation of male gamete during fertilization in mainly gymnosperms and angiosperms.
A. The birds had beaks that were adapted for feeding differently
Answer:
F1: Aa Bb Cc: 4.5 lbs
F2: Too many to list: Between 3 lbs and 6 lbs
Explanation:
F1: Aa Bb Cc, will be the genotypes and will weigh 4.5 lbs, the reason for that is because each capital letter allele adds half a pound to the base weight of 3 lbs.
F2: There are many different genotypes that can be present in the second generation, for example (AA BB CC, AA BB Cc, AA BB cc, etc.) each of which will allow the plant to grow to a certain height. The majority of phenotypes will be 4.5 lbs. There will be one who is AA BB CC, and another one person who has the code, aa bb cc.
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
