Alright, for 10, let's see 2(x+3). Use the distributive property to multiply 2 with x, which is 2x. Then, multiply 2 with 3, which is 6. Add them together to get 2x+6. For the second part, 4 times x is 4x and 4 times negative 2 is -8. Add them all up and you get 2x+6+4x-8=6x-2. Remember that you can't add a variable with other variables/just numbers, and a minus sign in front of terms in parenthesis means that everything in the parenthesis is negative!
Maybe you should work on starting you're sentences.
Answer:
C
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 4x + 9 ← is in slope- intercept form
with slope m = - 4
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
= 
, hence
y = x + c ← is the partial equation of the perpendicular line
To find c substitute (4, 5) into the partial equation
5 = 1 + c ⇒ c = 5 - 1 = 4
y = x + 4 ← equation of perpendicular line → C
Answer:
x = -2
TU = 4
UB = 2
Step-by-step explanation:
you can add x^2 with 4x+10 and equate it to 6:
x^2 + 4x + 10 = 6
x^2 + 4x + 4
then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a
so it'll be x = {-4±[√16 - 4(4)]}/2
x= -2
then u can substitute it and find TU and UB
TU= (-2)^2 = 4
UB= 4(-2)+10 = 2
